我试图在Doctrine 2的场景中实现以下内容:
这类似于“船长”中的以下内容:

将导出到基于Doctrine 2注释的实体时,如下所示(Getter和setter被剪短):
Driver.php
<?php
namespace Racing\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* @ORM\Entity
*/
class Driver
{
/**
* @ORM\Id
* @ORM\Column(type="bigint")
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $Id;
/**
* @ORM\Column(type="text", nullable=false)
*/
private $Name;
}Vehicle.php
<?php
namespace Racing\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* @ORM\Entity
*/
class Vehicle
{
/**
* @ORM\Id
* @ORM\Column(type="bigint")
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $Id;
/**
* @ORM\Column(type="text", nullable=false)
*/
private $Name;
}Race.php
<?php
namespace Racing\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* @ORM\Entity
*/
class Race
{
/**
* @ORM\Id
* @ORM\Column(type="integer")
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $Id;
/**
* @ORM\Column(type="text", nullable=false)
*/
private $Name;
}Accident.php
<?php
namespace Racing\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* @ORM\Entity
*/
class Accident
{
/**
* @ORM\Column(type="text", nullable=false)
*/
private $Description;
/**
* @ORM\ManyToOne(targetEntity="Racing\Entity\RacingVehicle")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="Racing_Vehicle_Driver_Id", referencedColumnName="Driver_Id", nullable=false),
* @ORM\JoinColumn(name="Racing_Vehicle_Vehicle_Id", referencedColumnName="Vehicle_Id", nullable=false)
* })
*/
private $RacingVehicle;
/**
* @ORM\Id
* @ORM\ManyToOne(targetEntity="Racing\Entity\Race")
* @ORM\JoinColumn(name="Race_Id", referencedColumnName="Id", nullable=false)
*/
private $Race;
}RacingVehicle.php
<?php
namespace Racing\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* @ORM\Entity
*/
class RacingVehicle
{
/**
* @ORM\Column(type="integer", nullable=false)
*/
private $Startnumber;
/**
* @ORM\Id
* @ORM\ManyToOne(targetEntity="Racing\Entity\Driver")
* @ORM\JoinColumn(name="Driver_Id", referencedColumnName="Id", nullable=false)
*/
private $Driver;
/**
* @ORM\Id
* @ORM\ManyToOne(targetEntity="Racing\Entity\Vehicle")
* @ORM\JoinColumn(name="Vehicle_Id", referencedColumnName="Id", nullable=false)
*/
private $Vehicle;
}测试示例如下所示:
// Get the entity manager
$sservicelocator = $this->getServiceLocator();
$entitymanager = $sservicelocator->get('doctrine.entitymanager.orm_default');
// Create a driver
$driver = new Driver();
$driver->setName("Michael Schumacher");
$entitymanager->persist($driver);
// Create a vehicle
$vehicle = new Vehicle();
$vehicle->setName("Ferrari");
$entitymanager->persist($vehicle);
// Create a race
$race = new Race();
$race->setName("Monaco");
$entitymanager->persist($race);
// Create a racing vehicle
$racingvehicle = new RacingVehicle();
$racingvehicle->setDriver($driver);
$racingvehicle->setVehicle($vehicle);
$racingvehicle->setStartnumber(42);
$entitymanager->persist($racingvehicle);
// Create an accident
$accident = new Accident();
$accident->setRace($race);
$accident->setRacingVehicle($racingvehicle);
$entitymanager->persist($accident); // <-------------- Error line
// Flush
$entitymanager->flush();当我试图坚持这个事故的时候,我就会得到这样的错误:
The given entity of type 'Racing\Entity\Accident' (Racing\Entity\Accident@0000000072a5fbd400007f1c433b761e) has no identity/no id values set. It cannot be added to the identity map.因此,我的问题是:如何创建一个以RacingVehicle和Race为主键的实体(意外),同时真正拥有自己的PHP实体(我可以创建多到多的关系,但在这种情况下,我不会有自己的意外实体)。
发布于 2016-11-09 09:03:22
我认为您可以将Driver和Vehicle作为ids添加到RacingVehicle中。那么Accident看起来会是这样的:
<?php
namespace Racing\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* @ORM\Entity
*/
class Accident
{
//...
/**
* @ORM\Id
* @ORM\ManyToOne(targetEntity="Racing\Entity\Driver")
* @ORM\JoinColumn(name="Driver_Id", referencedColumnName="Id", nullable=false)
*/
private $Driver;
/**
* @ORM\Id
* @ORM\ManyToOne(targetEntity="Racing\Entity\Vehicle")
* @ORM\JoinColumn(name="Vehicle_Id", referencedColumnName="Id", nullable=false)
*/
private $Vehicle;
/**
* @ORM\Id
* @ORM\ManyToOne(targetEntity="Racing\Entity\Race")
* @ORM\JoinColumn(name="Race_Id", referencedColumnName="Id", nullable=false)
*/
private $Race;
//...
}这意味着您将得到一个由三列组成的组合键。现在可以使用Driver_Id列和Vehicle_Id列来解决事故中的RacingVehicle。
不确定是否可以直接映射它,因为它可能会导致相互冲突的索引(因为Driver_Id的索引与Driver表中的标识符绑定,Vehicle_Id的索引绑定到Vehicle表中的标识符),但您可以在生命周期事件中向RacingVehicle加载或创建代理。
https://stackoverflow.com/questions/40497077
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