如何编写EF7 (核心)/ SQL友好的多到多LINQ查询?
比如说,我有很多会说多种语言的朋友,我想为一套语言找到所有的朋友。
class Friend
{
Guid Id { get; set; }
ICollection<FriendLanguage> Languages { get; set; }
}
class Language
{
Guid { get; set; }
ICollection<FriendLanguage> Friends { get; set; }
}
class FriendLanguage
{
Friend { get; set; }
Language { get; set; }
}考虑到我有一组语言I IEnumerable<Guid>,我想找回所有讲这些语言的朋友。
我试过这个..。
friends
.Include(o => o.Languages).ThenInclude(o => o.Language)
.SelectMany(o => o.Languages).Select(o => o.Language.Id)
.Intersect(languages);...but --它只返回一组简化的Guids...not,它完全确定从这里到哪里,或者即使我在正确的路径上。
发布于 2016-11-07 21:15:58
如果我的理解是正确的,你想让那些会说语言的朋友们把所有的语言都从列表中拿出来。
表达您的需求的最自然的LINQ查询是:
var friends = db.Friends
.Include(o => o.Languages).ThenInclude(o => o.Language)
.Where(o => languages.All(id => o.Languages.Any(fl => fl.Language.Id == id)));不幸的是,它不是SQL友好的。事实上,memory目前无法将其转换为SQL,而是会读取内存中的数据并在其中进行筛选。
所以你可以用这个代替:
var friends = db.Friends
.Include(o => o.Languages).ThenInclude(o => o.Language)
.Where(o => o.Languages.Count(fl => languages.Contains(fl.Language.Id)) == languages.Count);这意味着这样的事情:
SELECT [o].[Id]
FROM [Friends] AS [o]
WHERE (
SELECT COUNT(*)
FROM [FriendLanguages] AS [fl]
WHERE [fl].[LanguageId] IN ('6e64302f-24db-4717-a5fe-2cc61985ca3a', '2c216a63-1f6a-4fad-9105-d5f8ece3fa3c') AND ([o].[Id] = [fl].[FriendId])
) = @__languages_Count_1
ORDER BY [o].[Id]如果您确实希望使用列表中语言的的朋友,那么Where就更简单了:
.Where(o => o.Languages.Any(fl => languages.Contains(fl.Language.Id)))SQL是:
SELECT [o].[Id]
FROM [Friends] AS [o]
WHERE EXISTS (
SELECT 1
FROM [FriendLanguages] AS [fl]
WHERE [fl].[LanguageId] IN ('ed3f85a7-e122-45dd-b0af-2020052d55a7', '4819cb7d-ad43-41a0-a3a1-979b7abc6265') AND ([o].[Id] = [fl].[FriendId]))
ORDER BY [o].[Id]https://stackoverflow.com/questions/40474349
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