graphene.Mutation的窃听器？

Question

我使用石墨烯-django来拥有一个GrapQL API。我在我的schema.py中创建了一个突变

class UpdateApplication(graphene.Mutation):
    class Input:
        id = graphene.String()
        name = graphene.String()

    application = graphene.Field(ApplicationNode)

    @classmethod
    def mutate(cls, instance, args, info):
        name = args.get('name')
        rid = from_global_id(args.get('id'))[1]
        update_application = Application.objects.filter(id=rid).update(name=name)

        return UpdateApplication(application=update_application)



class Mutation(ObjectType):
    update_application = UpdateApplication.Field()

schema = graphene.Schema(mutation=Mutation)

当我运行这个搜索时，我有一个错误。

mutation update {
  updateApplication(id: "QXBwbGljYXRpb25Ob2RlOjE=", name: "foo") {
    application {
      name
    }
  }
}

错误：

mutate() takes exactly 4 arguments (5 given)

我提出了4个论点的变异()而不是5.是虫子吗？

Answer 1

从石墨烯1.0开始，上下文在默认情况下被传递给突变和解析函数，而在以前的版本中它需要@with_context：https://github.com/graphql-python/graphene/blob/master/UPGRADE-v1.0.md

因此，您的变异函数应该如下所示：

def mutate(self, args, context, info):
    name = args.get('name')
    rid = from_global_id(args.get('id'))[1]
    update_application = Application.objects.filter(id=rid).update(name=name)

    return UpdateApplication(application=update_application)