替换列表中的条目(sentence.replace())

Question

我正试着建立一个基于文本的冒险游戏。我仍然处于开发的早期阶段，在将给定的句子等同于定向和或动作命令方面，我遇到了很多问题。这是我到目前为止所得到的一些片段。将得到错误“列表对象没有属性替换”：

sentence_parsing = input().split(" ")

travel = ["Move", "move", "MOVE", "Go", "go", "GO", "Travel", "travel", "TRAVEL"]
command_length = len(sentence_parsing)
for command in range(command_length):
    for action in range(9):
        if travel[action] == sentence_parsing[command]:
            sentence_parsing = sentence_parsing.replace(travel[action], "1")

在将值应用到已知关键字之后，我需要删除所有未知单词，我认为这可以使用类似的嵌套循环来完成，检查原始句子和修改后的单词是否有匹配的单词，如果有，则删除。在此之后，我需要使列表中的字符串数值变为整数，并将它们相乘。我确实有可选择的逻辑来纠正句子中的否定，但它工作得很好。如能提供任何帮助，将不胜感激。

Answer 1

与其在travel中迭代，不如使用sentence_parsing中的单词进行迭代。

# Make sure that your parser is not case-sensitive by transforming 
# all words to lower-case:
sentence_parsing = [x.lower() for x in input().split(" ")]

# Create a dictionary with your command codes as keys, and lists of 
# recognized command strings as values. Here, the dictionary contains
# not only ``travel'' commands, but also ``eat'' commands:
commands = {
    "1": ["move", "go", "travel"],
    "2": ["consume", "gobble", "eat"]}

# Iterate through the words in sentence_parsing. 
# ``i'' contains the index in the list, ``word'' contains the actual word:
for i, word in enumerate(sentence_parsing):
    # for each word, go through the keys of the command dictionary:
    for code in commands:
         # check if the word is contained in the list of commands 
         # with this code: 
         if word in commands[code]:
             # if so, replace the word by the command code:
             sentence_parsing[i] = code

使用输入字符串

往北走。吃水果。往东走。吃掉妖精。

在代码执行之后，列表sentence_parsing如下所示：

['1', 'north.', '2', 'fruit.', '1', 'east.', '2', 'goblin.']

Answer 2

input().split()

留给您一个字符串列表。您可以使用for循环一次检查它们。

for command in sentence_parsing:
    if command in travel:
        #do something
    else:
        #do a different thing

如果你只想保留你在旅行中认出的单词，你可以这样做：

sentence_parsing = [command for command in sentence_parsing if command in travel]

Answer 3

试试这个：

travel[action] = "1"

但是我认为你必须使用dict，或者给列表中的特定数字赋值。例如：

>>>list = [0, 0]
>>>list
[0, 0]
>>>list[1] = "1"
>>>list
[0, '1']

您必须将.replace()应用于列表中的字符串，而不是完整的列表。像这样：travel[0].replace()