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NLP带球拍
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Stack Overflow用户
提问于 2016-10-25 13:10:51
回答 2查看 487关注 0票数 1

我正在用球拍和博士学习NLP。

我正在处理以下代码:

代码语言:javascript
复制
#lang racket

(define english-1
  '((Initial (1))
    (Final (9))
    (From 1 to 3 by NP)
    (From 1 to 2 by DET)
    (From 2 to 3 by N)
    (From 3 to 4 by BV)
    (From 4 to 5 by ADV)
    (From 4 to 5 by |#|)
    (From 5 to 6 by DET)
    (From 5 to 7 by DET)
    (From 5 to 8 by |#|)
    (From 6 to 7 by ADJ)    
    (From 6 to 6 by MOD)
    (From 7 to 9 by N)
    (From 8 to 8 by MOD)
    (From 8 to 9 by ADJ)
    (From 9 to 4 by CNJ)
    (From 9 to 1 by CNJ)))

(define (getf x y)
  (if (eq? (car x) y)
      (cadr x)
      (getf (cdr x) y)))

(define (initial-nodes network)
  (list-ref (assoc 'Initial network) 1))

(define (final-nodes network)
  (list-ref  (assoc 'Final network) 1))

(define (transitions network)
  (filter (lambda (x) (eq? (car x) 'From)) network))

(define (trans-node transition)
  (getf transition 'From))

(define(trans-newnode transition)
  (getf transition 'to))

(define (trans-label transition)
  (getf transition 'by))

(define abbreviations
  '((NP kim sandy lee)
    (DET a the her)
    (N consumer man woman)
    (BV is was)
    (CNJ and or)
    (ADJ happy stupid)
    (MOD very)
  (ADV often always sometimes)))

(define (recognize network tape)
  ;; returns t if sucessfully recognizes tape - nil otherwise
  (call/cc (lambda (return)
             (define (recognize-next node tape network)
               (if (and (null? tape) (member node (final-nodes network)))
                   (return #t) ; success
                   (for ([transition (transitions network)])
                           ;; try each transition of the network
                           (when (equal? node (trans-node transition)) ; if it starts at the right node
                               (for ([newtape (recognize-move (trans-label transition) tape)])
                                       ;; try each possible new value of tape
                                 (recognize-next (trans-newnode transition) newtape network))))))
             (for ([initialnode (initial-nodes network)])
               (recognize-next initialnode tape network))
             null))) ; failed to recognize

(define (recognize-move label tape)
  (if (or (eq? label (car tape))
          (member (car tape) (assoc label abbreviations)))
      (list (cdr tape))
      (if (eq? label '|#|)
          (list tape)
          null)))

(require racket/trace)
(trace recognize-move)
(recognize-move english-1 '(hahaha))

代码似乎大部分都没问题。但是,我一直收到一个与识别-移动函数相关的错误消息:

代码语言:javascript
复制
member: not a proper list: #f

我以为我在处理名单..。我怎么才能解决这个问题?

EN

回答 2

Stack Overflow用户

回答已采纳

发布于 2016-10-25 13:33:23

问题在于这种形式:

代码语言:javascript
复制
(member (car tape) (assoc label abbreviations))

如果assoc找不到任何东西,结果就是#f(member 'anything #f)将无法工作。在公共项中,Lisp与空列表相同,因此在false上的member将有效,但在Scheme中不起作用。您也许可以确定这是一个这样的列表:

代码语言:javascript
复制
(member (car tape) (or (assoc label abbreviations) '()))
票数 3
EN

Stack Overflow用户

发布于 2016-10-25 13:44:39

这是从Common翻译过来的代码。在CL中,nil是false,也是空列表()。在球拍中,#f是假的,与()不一样。如果没有找到匹配项,assoc希望返回false :由于CL对false的双关语和空列表的方式,这意味着(member ... (assoc ...))将始终工作。在球拍中,它不会:你需要检查看看assoc是否找到匹配。

票数 2
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/40240929

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