如何删除句子中存在的像<U+0924><U+0930><U+0938><U+0902><U+0917><U+0924>这样的标记。Via- <U+0924><U+0930><U+094D><U+0915><U+0938><U+0902><U+0917><U+0924> - Tarksangat ~<U+0938><U+092F><U+094D><U+092F><U+0926> <U+092E><U+0902><U+095B><U+0930> <U+0907><U+092E><U+093E><U+092E>
我需要输出:Via- Tarksangat
有谁可以帮我?谢谢!
发布于 2016-10-23 05:00:48
希望这是有用的
ab <- unlist(strsplit(abc,"[[:punct:]]"))
ab <- gsub("[[:punct:]]|[0-9]","",ab)
ab <- paste0(ab[nchar(ab)>2],collapse="-")
[1] "Via- Tarksangat "数据
abc <- "Via- <U+0924><U+0930><U+094D><U+0915><U+0938><U+0902><U+0917><U+0924> - Tarksangat ~<U+0938><U+092F><U+094D><U+092F><U+0926> <U+092E><U+0902><U+095B><U+0930> <U+0907><U+092E><U+093E><U+092E>"发布于 2016-10-23 04:53:36
尝尝这个
<U.*?>并替换为空字符串
你可以试试这个:
re = /<U.*?>/
str = 'asdfasdf <U+0924><U+0930><U+0938><U+0902><U+0917> tsdfasf <U+0924> 1sadfasdf a2sdf 3sdafasdf <U+0924><U+0930>5<U+0938> 4asdfasdf <U+0902><U+0917><U+0924>'
subst = ''
result = str.gsub(re, subst)
# Print the result of the substitution
puts resulthttps://stackoverflow.com/questions/40199632
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