下面的代码怎么会起作用呢?我想每隔200毫秒向ArrayList添加新的卵形,并逐一显示并运行它们。当我运行一个粒子s.runner()时,它工作得很好;但是它似乎并不能运行我的所有粒子。
主要:
import java.awt.EventQueue;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.ArrayList;
import javax.swing.JFrame;
import javax.swing.Timer;
public class ExempelGraphics extends JFrame implements ActionListener {
Timer t;
private int inc = 0;
ArrayList<Surface> particle = new ArrayList<>();
Surface s;
public ExempelGraphics() {
t = new Timer(10, this);
t.start();
s = new Surface(10, 10);
initUI();
}
private void initUI() {
add(s);
setSize(350, 250);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
}
public void actionPerformed(ActionEvent e) {
// s.runner();
// add
if (inc++ % 20 == 0) {
particle.add(new Surface(10, 10));
}
// display
for (int i = 0; i < particle.size(); i++) {
Surface p = particle.get(i);
p.runner();
}
}
public static void main(String[] args) {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
ExempelGraphics ex = new ExempelGraphics();
ex.setVisible(true);
}
});
}
}图形:
import java.awt.Color;
import java.awt.Graphics;
import java.awt.Graphics2D;
import javax.swing.JPanel;
public class Surface extends JPanel {
private int locX = 0;
private int locY = 0;
public Surface(int locX, int locY) {
this.locX = locX;
this.locY = locY;
}
public void runner() {
locX = locX + 1;
repaint();
}
@Override
public void paintComponent(Graphics g) {
super.paintComponent(g);
Graphics2D g2d = (Graphics2D) g;
g2d.setColor(Color.RED);
g2d.fillOval(locX, locY, 10, 10);
}
}发布于 2016-10-17 21:20:14
我觉得你的程序结构坏了。这里应该只有一个JPanel进行绘图,它的paintComponent被重写,而您的JPanel类应该是一个逻辑类,而不是一个组件类--换句话说,不要让它扩展JPanel,并给它一个绘制椭圆的public void draw(Graphics g)方法。然后让绘图JPanel保存这些曲面的ArrayList,并在主JPanel的paintComponent方法中迭代这些曲面,调用每个曲面的绘图方法。
此外,您的计时器的延迟是不现实的,太小。15将更加现实。
另外,不要从表面调用repaint(),因为这会产生太多不必要的重绘调用。相反,在调用所有Surface对象上的runner方法之后,从计时器的ActionListener中调用它。
还请注意,每次以默认方式向JFrame的contentPane添加组件时,都会掩盖之前添加的组件。如果您按照我上面的建议,这并不是一个问题,因为您只需要将单个JPanel添加到其中。
例如:
import java.awt.Dimension;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.RenderingHints;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.ArrayList;
import java.util.List;
import javax.swing.*;
@SuppressWarnings("serial")
public class ExampleGraphics2 extends JPanel {
private static final int PREF_W = 650;
private static final int PREF_H = 500;
private static final int TIMER_DELAY = 20;
private List<Surface> surfaces = new ArrayList<>();
public ExampleGraphics2() {
new Timer(TIMER_DELAY, new TimerListener()).start();
}
@Override
protected void paintComponent(Graphics g) {
super.paintComponent(g);
Graphics2D g2 = (Graphics2D) g;
g2.setRenderingHint(RenderingHints.KEY_ANTIALIASING, RenderingHints.VALUE_ANTIALIAS_ON);
for (Surface surface : surfaces) {
surface.draw(g);
}
}
@Override
public Dimension getPreferredSize() {
if (isPreferredSizeSet()) {
return super.getPreferredSize();
}
return new Dimension(PREF_W, PREF_H);
}
private class TimerListener implements ActionListener {
private int index = 0;
@Override
public void actionPerformed(ActionEvent e) {
index++;
index %= 20;
if (index == 0) {
surfaces.add(new Surface(10, 10));
}
for (Surface surface : surfaces) {
surface.runner();
}
repaint();
}
}
private static void createAndShowGui() {
JFrame frame = new JFrame("Example Graphics 2");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.getContentPane().add(new ExampleGraphics2());
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
public static void main(String[] args) {
SwingUtilities.invokeLater(() -> createAndShowGui());
}
}
package foo1;
import java.awt.Color;
import java.awt.Graphics;
import java.awt.Graphics2D;
public class Surface {
private int locX = 0;
private int locY = 0;
public Surface(int locX, int locY) {
this.locX = locX;
this.locY = locY;
}
public void runner() {
locX = locX + 1;
}
public void draw(Graphics g) {
Graphics2D g2d = (Graphics2D) g;
g2d.setColor(Color.RED);
g2d.fillOval(locX, locY, 10, 10);
}
}https://stackoverflow.com/questions/40095785
复制相似问题