运行时优化的UV解包

Question

我试图创建UVs @ runtime，我使用的是一个盒子类型的UVs (类似于3ds max中的BOX UVW )，并根据脸的方向进行计算。

我知道创建它不是一个好的选择，但是我没有选择:(它是在计算后保存的，所以我做了一次。

但我花了40秒才有30000个顶点.太长了

我的代码中有任何可以进行的优化吗？

。

下面是我的代码，如果您有<5000顶点网格，可以随意使用：

public static void CreateUV(ref Mesh mesh)
{

    int i = 0;
    Vector3 p = Vector3.up;
    Vector3 u = Vector3.Cross(p, Vector3.forward);
    if (Vector3.Dot(u, u) < 0.001f)
    {
        u = Vector3.right;
    }
    else
    {
        u = Vector3.Normalize(u);
    }

    Vector3 v = Vector3.Normalize(Vector3.Cross(p, u));

    Vector2[] uvs = new Vector2[mesh.vertices.Length];

    for (i = 0; i < mesh.triangles.Length; i += 3)
    {

        Vector3 a = mesh.vertices[mesh.triangles[i]];
        Vector3 b = mesh.vertices[mesh.triangles[i + 1]];
        Vector3 c = mesh.vertices[mesh.triangles[i + 2]];
        Vector3 side1 = b - a;
        Vector3 side2 = c - a;
        Vector3 N = Vector3.Cross(side1, side2);

        N = new Vector3(Mathf.Abs(N.normalized.x), Mathf.Abs(N.normalized.y), Mathf.Abs(N.normalized.z));



        if (N.x > N.y && N.x > N.z)
        {
            uvs[mesh.triangles[i]] = new Vector2(mesh.vertices[mesh.triangles[i]].z, mesh.vertices[mesh.triangles[i]].y);
            uvs[mesh.triangles[i + 1]] = new Vector2(mesh.vertices[mesh.triangles[i + 1]].z, mesh.vertices[mesh.triangles[i + 1]].y);
            uvs[mesh.triangles[i + 2]] = new Vector2(mesh.vertices[mesh.triangles[i + 2]].z, mesh.vertices[mesh.triangles[i + 2]].y);
        }
        else if (N.y > N.x && N.y > N.z)
        {
            uvs[mesh.triangles[i]] = new Vector2(mesh.vertices[mesh.triangles[i]].x, mesh.vertices[mesh.triangles[i]].z);
            uvs[mesh.triangles[i + 1]] = new Vector2(mesh.vertices[mesh.triangles[i + 1]].x, mesh.vertices[mesh.triangles[i + 1]].z);
            uvs[mesh.triangles[i + 2]] = new Vector2(mesh.vertices[mesh.triangles[i + 2]].x, mesh.vertices[mesh.triangles[i + 2]].z);
        }
        else if (N.z > N.x && N.z > N.y)
        {
            uvs[mesh.triangles[i]] = new Vector2(mesh.vertices[mesh.triangles[i]].x, mesh.vertices[mesh.triangles[i]].y);
            uvs[mesh.triangles[i + 1]] = new Vector2(mesh.vertices[mesh.triangles[i + 1]].x, mesh.vertices[mesh.triangles[i + 1]].y);
            uvs[mesh.triangles[i + 2]] = new Vector2(mesh.vertices[mesh.triangles[i + 2]].x, mesh.vertices[mesh.triangles[i + 2]].y);
        }

    }

    mesh.uv = uvs;
    Debug.Log("Finish");
}

Answer 1

我强烈建议缓存mesh.vertices的副本。

vertices属性的文档部分说明如下：

返回顶点位置的副本或分配一个新的顶点位置数组。

注：“返回副本”--在循环中访问该属性22次，因此这将大致创建该数组的22n / 3副本。对于一个有30,000个顶点的网格来说，在后台进行的拷贝操作超过20万次。

如果您创建一个临时数组来保存顶点数据(就像您已经在使用mesh.uvs一样)，那么您将看到性能的显著提高。

还可以检查mesh.triangles是否是复制操作。我预计可能是这样，但文档没有指定。

Answer 2

这是我的代码经过了优化，这要归功于@rutter

public static Vector2[] CreateUV(ref Mesh mesh)
{

    int i = 0;
    Vector3 p = Vector3.up;
    Vector3 u = Vector3.Cross(p, Vector3.forward);
    if (Vector3.Dot(u, u) < 0.001f)
    {
        u = Vector3.right;
    }
    else
    {
        u = Vector3.Normalize(u);
    }

    Vector3 v = Vector3.Normalize(Vector3.Cross(p, u));
    Vector3[] vertexs = mesh.vertices;
    int[] tris = mesh.triangles;
    Vector2[] uvs = new Vector2[vertexs.Length];

    for (i = 0; i < tris.Length; i += 3)
    {

        Vector3 a = vertexs[tris[i]];
        Vector3 b = vertexs[tris[i + 1]];
        Vector3 c = vertexs[tris[i + 2]];
        Vector3 side1 = b - a;
        Vector3 side2 = c - a;
        Vector3 N = Vector3.Cross(side1, side2);

        N = new Vector3(Mathf.Abs(N.normalized.x), Mathf.Abs(N.normalized.y), Mathf.Abs(N.normalized.z));



        if (N.x > N.y && N.x > N.z)
        {
            uvs[tris[i]] = new Vector2(vertexs[tris[i]].z, vertexs[tris[i]].y);
            uvs[tris[i + 1]] = new Vector2(vertexs[tris[i + 1]].z, vertexs[tris[i + 1]].y);
            uvs[tris[i + 2]] = new Vector2(vertexs[tris[i + 2]].z, vertexs[tris[i + 2]].y);
        }
        else if (N.y > N.x && N.y > N.z)
        {
            uvs[tris[i]] = new Vector2(vertexs[tris[i]].x, vertexs[tris[i]].z);
            uvs[tris[i + 1]] = new Vector2(vertexs[tris[i + 1]].x, vertexs[tris[i + 1]].z);
            uvs[tris[i + 2]] = new Vector2(vertexs[tris[i + 2]].x, vertexs[tris[i + 2]].z);
        }
        else if (N.z > N.x && N.z > N.y)
        {
            uvs[tris[i]] = new Vector2(vertexs[tris[i]].x, vertexs[tris[i]].y);
            uvs[tris[i + 1]] = new Vector2(vertexs[tris[i + 1]].x, vertexs[tris[i + 1]].y);
            uvs[tris[i + 2]] = new Vector2(vertexs[tris[i + 2]].x, vertexs[tris[i + 2]].y);
        }

    }

    mesh.uv = uvs;
    return uvs;
}