我使用jplist插件并遵循贡献者的建议来切换排序。
但是有多个数据属性选择器的问题。
要触发,我需要通过数据路径、数据顺序等多个属性来选择元素,我不知道为什么:我不能使用具有多个属性的选择器触发。控制台不会显示任何错误。只是这不管用
$('#toggle-order1').click(function() {
// current sort button selected in sort group 1 -- return data-path
var sortpath1 = $('#sortgroup1 .jplist-selected').attr('data-path');
// current sort button selected in sort group 1 -- return data-order
var sortorder1 = $('#sortgroup1 .jplist-selected').attr('data-order');
if (sortorder1 == 'asc') {
// *** This doesn't click any button
$('button[data-path="' + sortpath1 + '"] [data-order="desc"]').trigger('click');
// *** This work but click all buttons that have data-path equals to sortpath1
$('button[data-path="' + sortpath1 + '"]').trigger('click');
}
else if (sortorder1 == 'desc') {
// *** This doesn't click any button
$('button[data-path="' + sortpath1 + '"] [data-order="asc"]').trigger('click');
// *** This work but click all buttons that have data-path equals to sortpath1
$('button[data-path="' + sortpath1 + '"]').trigger('click');
}
});html按钮:
<div id="sortgroup1" class="jplist-box" data-control-type="sort-buttons-group" data-control-name="sort-buttons-group-1" data-control-action="sort" data-mode="single">
<button id="set-asc-1" name="set" class="jplist-drop-down" data-path=".set" data-group="group1" data-type="text" data-order="asc" data-selected="false">
Sort by Set AZ
</button>
<button id="set-desc-1" name="set" class="jplist-drop-down" data-path=".set" data-group="group1" data-type="text" data-order="desc" data-selected="false">
Sort by Set ZA
</button>
<button id="price-asc-1" name="price" class="jplist-drop-down" data-path=".price" data-group="group1" data-type="number" data-order="asc" data-selected="false">
Sort by Price ASC
</button>
<button id="price-desc-1" name="price" class="jplist-drop-down" data-path=".price" data-group="group1" data-type="number" data-order="desc" data-selected="false">
Sort by Price DESC
</button>
</div>html切换
<button id="toggle-order1"><i class="fa"></i></button>欢迎所有建议。
发布于 2016-10-09 21:28:58
您必须删除属性之间的空格,因此
$('button[data-path="' + sortpath1 + '"] [data-order="desc"]')变成这样
$('button[data-path="' + sortpath1 + '"][data-order="desc"]')
// ^^ look ma, no space否则,您将寻找子代元素,就像使用
$('div span')https://stackoverflow.com/questions/39948640
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