PHP: Isset with语句

Question

iso.obj.php

$from = null;
$too = null;

if (isset($_POST['search'])) {
    if ($from = null) {
        $from = date("Y-m-d");
    } else {
        $from = $_POST['FromDateTime'];
    }

    if ($too = null) {
        $too = date('Y-m-d', strtotime("+30 days")) . " 23:59:59"; 
    } else {
        $too = $_POST['ToDateTime']." 23:59:59";
    }
}
$sql ="//statement here with
WHERE capDateTime >='{$from}' AND capDateTime <='{$too}'";

代码运行良好，但是当person请求页面并返回空表时，我遇到了问题。但是如果我选择日期和时间，它将根据日期和时间显示。

我的问题是:如果没有设置当前日期，那么如何将当前日期放置在$_POST之后？

Answer 1

$from = date("Y-m-d");
$too = date('Y-m-d', strtotime("+30 days")) . " 23:59:59";

if (isset($_POST['search'])) {
    if (!empty($_POST['FromDateTime'])) {
        $from = $_POST['FromDateTime'];
    }

    if (!empty($_POST['ToDateTime'])) {
        $from = $_POST['ToDateTime']." 23:59:59";
    }
}