我试图通过composeView对象使用因博克附加一个附件。我使用以下代码从远程url获取blob对象。
// FUNCTION TO OPEN A NEW COMPOSE BOX ONCE THE ATTACHMENT BLOB IS OBTAINED FROM REMOTE URL.
function openComposeBox(sdk, blob){
handler = sdk.Compose.registerComposeViewHandler(function(composeView){
if(blob != null){
composeView.attachFiles([blob]);
composeView.setSubject("Testing");
}
});
}
// FETCHING ATTACHMENT FILE FROM REMOTE URL
var file_btn_url = "https://api.hummingbill.com/system/invoices/invoice_files/000/033/393/original/abracadabra.txt";
var file_name = file_btn_url.split("/");
file_name = file_name[file_name.length-1];
file_type = /[^.]+$/.exec(file_name);
var blob = null;
var xhr = new XMLHttpRequest();
xhr.open("GET", file_btn_url);
xhr.responseType = "blob";
xhr.onload = function()
{
blob = xhr.response;
// blob.lastModifiedDate = new Date(); // Since it's not necessary to have it assigned, hence commented.
blob.name = file_name;
console.log(blob);
openComposeBox(sdk, blob);
}
xhr.send();它显示了附件失败的错误。


虽然我有正确的blob对象格式,但按照文档的要求,是正确的。

根据文档,我已经为blob设置了文件名,并将它在数组中传递给attachFiles函数。请你调查一下,让我知道我缺少了什么吗?
发布于 2018-12-13 10:04:51
张贴解决方案。代码与问题相同,只是略有变化,我们将blob转换为一个文件,以使其工作。
//... Same as the code in the question
// Fetching attachment file from remote url
var file_btn_url = "https://api.hummingbill.com/system/invoices/invoice_files/000/033/393/original/abracadabra.txt";
var file_name = file_btn_url.split("/");
file_name = file_name[file_name.length-1];
file_type = /[^.]+$/.exec(file_name);
var blob = null;
var xhr = new XMLHttpRequest();
xhr.open("GET", file_btn_url);
xhr.responseType = "blob";
xhr.onload = function()
{
// Solution: Convert the obtained blob to a file
// Pass the file to openComposeBox
blob = new Blob([xhr.response], { type: xhr.responseType });
var file = new File([blob], file_name);
blob.name = file_name;
openComposeBox(sdk, file);
}
xhr.send();希望这能有所帮助。干杯!
https://stackoverflow.com/questions/39876901
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