二进制-十六进制转换器

Question

我编写了一个代码，试图将一个4位二进制数字转换为十六进制.唯一的问题是，当我键入一个以'1‘开头的值时，它会产生转换，而如果我键入一个以'0’开头的值，则不起作用。有什么帮助吗？

print ("""Here's how the program will work. You need to get your binary number ready.
        if it is 8 bit, split it into four, because thats how hexadecimal works. Make sure all your conversions
        are slip into '4' bits like this:
        01001101 will turn into:
        0100 ,and then 1101""")
time.sleep(6)
print ("""So, for example, the program will ask you for your binary number. Like this:
        Enter your binary number here:
        Then you put in your number, like this:
        Enter your binary number here: 0100
        Lastly, the program will give you your hexadecimal number, then ask you if you would
        like to do another conversion in this area, or end program.""")
time.sleep(6)
HEXADECIMAL = int(input("Please enter your binary number here:   "))                         
if HEXADECIMAL == 0000:
    print ("Your hexadecimal value is 0")
if HEXADECIMAL == 0001:
    print ("Your hexadecimal value is 1")
if HEXADECIMAL == 0010:
    print ("Your hexadecimal value is 2")
if HEXADECIMAL == 0011:
    print ("Your hexadecimal value is 3")
if HEXADECIMAL == 0100:
    print ("Your hexadecimal value is 4")
if HEXADECIMAL == 0101:
    print ("Your hexadecimal value is 5")
if HEXADECIMAL == 0110:
    print ("Your hexadecimal value is 6")
if HEXADECIMAL == 0111:
    print ("Your hexadecimal value is 7")
if HEXADECIMAL == 1000:
    print ("Your hexadecimal value is 8")
if HEXADECIMAL == 1001:
    print ("Your hexadecimal value is 9")
if HEXADECIMAL == 1010:
    print ("Your hexadecimal value is A")
if HEXADECIMAL == 1011:
    print ("Your hexadecimal value is B")
if HEXADECIMAL == 1100:
    print ("Your hexadecimal value is C")
if HEXADECIMAL == 1101:
    print ("Your hexadecimal value is D")
if HEXADECIMAL == 1110:
    print ("Your hexadecimal value is E")
if HEXADECIMAL == 1111:
    print ("Your hexadecimal value is F")

您可以尝试运行这段代码，并从0110开始，但是它不会转换。有什么帮助吗？

Answer 1

您不必每次都使用if/else语句。有一种很酷的方法可以在python中使用int()，如果您使用一个字符串，int()函数可以直接将它转换为任何基。

HEXADECIMAL = str(input())

base = 16 # for Hex and 2 for binary
msg = "Your hexadecimal value is"
print (msg, int(HEXADECIMAL, base))

这会帮你的。但是，如果您想继续使用您的方法，那么您可能应该在二进制之前在0b中添加一个0b0010，并执行一些操作，前导零是非法的，0010是非法的。

Answer 2

当输入以前导0开头的整数时，python将其解释为基数为8：

a = 0110
print a

威尔输出

72

因此，在您的输入中删除前面的0，或者在对其进行int()转换之前删除它们。

Answer 3

替换，

HEXADECIMAL = int(input("Please enter your binary number here:   ")) 

带着，

temp = input("Please enter your binary number here:   ")                       
HEXADECIMAL = int (temp)

另外，如果出现错误，则删除睡眠时间。