我想了解一下我的sql作业,它包含
name job_id run_date LastSuccessfulRunDate
这是我最后一次成功的运行日期的发现。工作很有魅力,但我在这里,没有添加最后的运行日期。
Use msdb
GO
SELECT
SJ.NAME AS [Job Name]
,RUN_STATUS AS [Run Status]
,MAX(DBO.AGENT_DATETIME(RUN_DATE, RUN_TIME)) AS [Last Time Job Ran On]
FROM
dbo.SYSJOBS SJ
LEFT OUTER JOIN dbo.SYSJOBHISTORY JH
ON SJ.job_id = JH.job_id
WHERE JH.step_id = 0
AND jh.run_status = 1
GROUP BY SJ.name, JH.run_status
ORDER BY [Last Time Job Ran On] DESC
GO这是我到目前为止得到的结果,但是它给了我两行结果,一行是最后一次运行日期,另一行是最后一次成功运行(这是als不正确的,因为它选择了最高日期-不同的值)。我恳请帮助,以获得正确的连接和结果在一行。
USE msdb
GO
SELECT DISTINCT SJ.Name AS JobName,
SJH.run_date AS LastRunDate,
SJH.job_id,
(SELECT MAX(DBO.AGENT_DATETIME(RUN_DATE, RUN_TIME))
FROM sysjobs
RIGHT JOIN sysjobhistory
ON SJ.job_id = SJH.job_id
WHERE SJH.run_status = 1) AS LastSuccessfulRun,
CASE SJH.run_status
WHEN 0 THEN 'Failed'
WHEN 1 THEN 'Successful'
WHEN 3 THEN 'Cancelled'
WHEN 4 THEN 'In Progress'
END AS LastRunStatus
FROM sysjobhistory SJH, sysjobs SJ
WHERE SJH.job_id = SJ.job_id and SJH.run_date =
(SELECT MAX(SJH.run_date) FROM sysjobhistory SJH WHERE SJ.job_id = SJH.job_id)发布于 2016-10-25 12:13:41
解决办法是:
SELECT sj.name,
MAX(dbo.agent_datetime(sjh.run_date, sjh.run_time)) AS last_Succesful_run,
x.last_Unsuccesful_run
FROM sysjobhistory sjh
INNER JOIN sysjobs sj ON sjh.job_id = sj.job_id
LEFT OUTER JOIN
(SELECT sysjobs.name,
MAX(dbo.agent_datetime(sysjobhistory.run_date, sysjobhistory.run_time)) AS last_Unsuccesful_run
FROM sysjobhistory
INNER JOIN sysjobs ON sysjobhistory.job_id = sysjobs.job_id
WHERE sysjobhistory.run_status = 0
GROUP BY sysjobs.name) x
ON x.name = sj.name
WHERE run_status = 1
GROUP BY sj.job_id, sj.name, last_Unsuccesful_run放弃了公元前的状态,这样就足够清楚了。这一案件不是强制性的。
发布于 2016-09-27 12:55:03
我想你想要row_number()
SELECT x.*
FROM (SELECT SJ.NAME AS [Job Name], RUN_STATUS AS [Run Status],
DBO.AGENT_DATETIME(RUN_DATE, RUN_TIME) AS LastRunDateTime,
ROW_NUMBER() OVER (PARTITION BY SJ.NAME ORDER BY DBO.AGENT_DATETIME(RUN_DATE, RUN_TIME) DESC) as seqnum
FROM dbo.SYSJOBS SJ LEFT OUTER JOIN
dbo.SYSJOBHISTORY JH
ON SJ.job_id = JH.job_id
WHERE JH.step_id = 0 AND jh.run_status = 1
GROUP BY SJ.name, JH.run_status
) x
WHERE seqnum = 1
ORDER BY LastRunDateTime DESC;另外,学习使用正确、显式的JOIN语法。FROM子句中的逗号是古老的。
https://stackoverflow.com/questions/39725011
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