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社区首页 >问答首页 >重复注册时,节点快速服务器崩溃。

重复注册时,节点快速服务器崩溃。
EN

Stack Overflow用户
提问于 2016-09-21 16:24:18
回答 3查看 598关注 0票数 0

因此,我有一个节点服务器与api端点一起运行,当通过postman输入重复的电子邮件时,这个端点会不断崩溃。如果发生了不重复的注册,服务器将继续运行而不打嗝。但是,如果提交了重复的电子邮件,我确实看到邮递员有重复的电子邮件错误:

代码语言:javascript
复制
{
  "code": 11000,
  "index": 0,
  "errmsg": "E11000 duplicate key error collection: register.users index: email_1 dup key: { : \"atlanteavila@gmail.com\" }",
  "op": {
    "userRole": "isUser",
    "password": "yudfjadjslkafdaljj343",
    "zip": "94596",
    "state": "CA",
    "city": "Walnut Creek",
    "address2": "",
    "streetAddress": "1 fake address ",
    "phoneNumber": "(925) 555-0644",
    "email": "fake@email.com",
    "lastName": "Last",
    "firstName": "Person",
    "_id": "57e2b2e49f0de63201914616",
    "__v": 0
  }
}

下面是api路由:

代码语言:javascript
复制
var express = require('express');
var app = express();
var router = express.Router();
var User = require('../models/user');

module.exports = function (app) {

  router.route('/users')

  .get( function (req, res) {
    res.json({ message: 'welcome!!' });
  })

  .post(function (req, res) {
    var rb = req.body;
    var user = new User();
    user.firstName = rb.firstName;
    user.lastName = rb.lastName;
    user.email = rb.email;
    user.phoneNumber = rb.phoneNumber;
    user.streetAddress = rb.streetAddress;
    user.address2 = rb.address2;
    user.city = rb.city;
    user.state = rb.state;
    user.zip = rb.zip
    user.password = rb.password;
    user.userRole = rb.userRole;


    user.save( function(err) {
      if (err) {
        res.send(err);
        next();
      };
      res.json({ message: 'UserCreated!' });
    });
  });

  app.use('/api', router);

}

而猫鼬模式:

代码语言:javascript
复制
var mongoose = require('mongoose');
var Schema = mongoose.Schema;

var UserSchema = new Schema({
  firstName: {
    type: String,
    required: true
  },
  lastName: {
    type: String,
    required: true
  },
  email: {
    type: String,
    required: true,
    index: true,
    unique: true
  },
  phoneNumber: {
    type: String, 
    required: true
  },
  streetAddress: {
    type: String, 
    required: true
  },
  address2: String,
  city: {
    type: String, 
    required: true
  },
  state: {
    type: String, 
    required: true
  },
  zip: {
    type: String, 
    required: true
  },
  password: {
    type: String, 
    required: true
  },
  userRole: {
    type: String,
    required: true
  }
});

module.exports = mongoose.model('User', UserSchema);

最后,终端上的错误:

代码语言:javascript
复制
[nodemon] restarting due to changes...
[nodemon] starting `node server/server.js`
Up and running on port 3000
events.js:160
      throw er; // Unhandled 'error' event
      ^

Error: Can't set headers after they are sent.
    at ServerResponse.OutgoingMessage.setHeader (_http_outgoing.js:346:11)
    at ServerResponse.header (/Users/atlanteavila/Documents/myapps/register/node_modules/express/lib/response.js:719:10)
    at ServerResponse.send (/Users/atlanteavila/Documents/myapps/register/node_modules/express/lib/response.js:164:12)
    at ServerResponse.json (/Users/atlanteavila/Documents/myapps/register/node_modules/express/lib/response.js:250:15)
    at /Users/atlanteavila/Documents/myapps/register/server/routes/signUp.js:34:11
    at /Users/atlanteavila/Documents/myapps/register/node_modules/mongoose/lib/model.js:3336:16
    at /Users/atlanteavila/Documents/myapps/register/node_modules/mongoose/lib/document.js:1932:15
    at _combinedTickCallback (internal/process/next_tick.js:67:7)
    at process._tickCallback (internal/process/next_tick.js:98:9)
[nodemon] app crashed - waiting for file changes before starting...

谢谢你帮忙弄清楚这件事。谢谢!

EN

回答 3

Stack Overflow用户

回答已采纳

发布于 2016-09-21 17:17:17

您正在发送two响应,这就是为什么您要收到此错误

如果要在next()中发送响应,则不需要使用save function回调,这将是fail or success

在像这样的操作之后,尝试返回您的响应

代码语言:javascript
复制
user.save( function(err) {
      if (err) {
       return res.send(err);
      };
      return res.json({ message: 'UserCreated!' });
    });
票数 2
EN

Stack Overflow用户

发布于 2016-09-21 17:03:23

当出现错误(这是抛出异常)时,您将发送两个响应。您可以通过返回next()或在调用它之后返回来缓解这种情况。

代码语言:javascript
复制
user.save( function(err) {
  if (err) {
    return res.send(err);
  }
  res.json({ message: 'UserCreated!' });
});
票数 2
EN

Stack Overflow用户

发布于 2016-09-21 16:58:11

您有唯一的: true在您的模式中,当您试图插入一个重复的记录。这违反了架构验证规则。您应该对查询使用异常处理,并解析这些错误。您可以使用try-catch块,如果您使用的是承诺,那么在每个查询中使用catch块。

若要发送有关重复保存记录的响应,请执行以下操作。在路由器错误处理程序中添加以下内容:

代码语言:javascript
复制
if (err instanceof Error && err.name === "MongoError" && err.driver) {
        if (err.code == 11000) { // unique index conflict
            return ['Resource document already exists.'];
        }
    }

并从错误处理程序返回它。

票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/39621817

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