将带符号int号转换为无符号shell脚本

Question

我需要使用shell脚本将有符号的int32编号转换为无符号的

例如：

convert  Input : -256
Expected output: 4294967040

Answer 1

这能帮到你；

#!/bin/bash
input=$1
if [[ $input -lt "0" ]]; then
    output=$((4294967296+$input))
else
    output=$input
fi
echo $output


#signed int32;
#–2,147,483,648 to 2,147,483,647
#unsigned int32
#0 to 4,294,967,295

Answer 2

这可能不是最快的，但似乎起作用了

unsigned_to_signed()
{
    local hex=$(printf "0x%x" $(( $* )))
    local unsigned=$(printf "%u" $hex )
    echo $unsigned
}

unsigned_to_signed32()
{
    local hex=$(printf "0x%x" $(( $* & 0xFFFFFFFF )))
    local unsigned=$(printf "%u" $hex )
    echo $unsigned
}

unsigned_to_signed -256
18446744073709551360

unsigned_to_signed32 -256
4294967040