我被一个SQL查询困住了。我知道该怎么做,但我不知道怎么做。因此,以下是所需的计划:
电影(标题,导演,年份,体裁,比率);
TITLE DIRECTOR YEAR GENRE RATE
Fight club Fincher 1999 Action 4.5
Vertigo Hitchock 1958 Drama 5
Donnie darko Kelly 2001 Thriller 3.5 视频(标题,导演,胶体);
TITLE DIRECTOR COLLOC
Fight club Fincher 3877
Fight club Fincher 3878
Vertigo Hitchcock 5431
Vertigo Hitchcock 5432
Donnie darko Kelly 9986租金(colloc,dateRent,customer,dateReturn);
COLLOC DATERENT CUSTOMER DATERETURN
3877 2016-05-02 324 2016-05-04
3877 2016-05-20 365 2016-05-20
3878 2016-04-11 876 2016-04-12
3878 2016-06-06 112 2016-06-08
... ... ... ...
... ... ... ...
9986 2016-02-24 443 2016-02-28下面是一个查询:
列表中,每部电影至少租了多少个视频。
(注:该商店通常有更多的视频- dvds,vhs等-为每部电影)。
我的方法如下:我将从这个简单的查询开始
SELECT colloc, title, director, COUNT(colloc) AS rentNumber
FROM Rent
NATURAL JOIN Video
GROUP BY colloc要显示如下内容:
COLLOC TITLE DIRECTOR RENTNUMBER
3877 Fight club Fincher 2
3878 Fight club Fincher 2
5432 Vertigo Hitchcock 2
5431 Vertigo Hitchcock 1
9986 Donnie darko Kelly 1 为了达到这个目的:
TITLE DIRECTOR VIDEOSNUMBER
Fight club Fincher 2
Vertigo Hitchcock 1
Donnie darko Kelly 0但我错过了最后一步,我不能适当地使用组/拥有。即使有子查询也没有成功。我一直在尝试使用一种不同的方法,但我没有什么好的,所以任何提示都会被感激。
谢谢。
编辑:注意,没有必要在查询中使用表电影。我把它放在那里只是为了解释一部电影可以有不止一个视频。添加了表格示例。主键以粗体显示。
解决方案:由于你的技巧,我找到了一个解决方案(老实说,这是部分的,因为它释放了所有的影片,其中没有录影带,至少2次)。总之,这里是:
SELECT title, director, COUNT(title) AS videosNumber
FROM (SELECT colloc, title, director, COUNT(colloc) AS rentNumber
FROM rent NATURAL JOIN video
GROUP BY colloc
) X
WHERE rentNumber > 1
GROUP BY title发布于 2016-09-20 08:07:09
请尝试以下查询:
SELECT t1.TITLE,
t1.DIRECTOR,
COALESCE(t2.VIDEOSNUMBER, 0) AS VIDEOSNUMBER
FROM Movie t1
LEFT JOIN
(
SELECT v.TITLE, COUNT(DISTINCT r.COLLOC) AS VIDEOSNUMBER
FROM Rent r
INNER JOIN Video v
ON r.COLLOC = v.COLLOC
GROUP BY v.TITLE
) t2
ON t1.TITLE = t2.TITLE
ORDER BY COALESCE(t2.VIDEOSNUMBER, 0) DESC发布于 2016-09-20 07:09:55
尝尝这个
SELECT
-- if you want to add colloc, uncomment below
-- r.colloc as COLLOC
m.title as TITLE,
m.director as DIRECTOR,
COUNT(r.colloc) as VIDEOSNUMBER
FROM movie m
LEFT JOIN video v ON m.title = v.title
LEFT JOIN rent r ON v.colloc = r.colloc
GROUP BY TITLE发布于 2016-09-20 07:10:47
测试了它:
SELECT m.TITLE, m.DIRECTOR, COALESCE(rs.Rentnumber, 0) AS VIDEOSNUMBER
FROM Movie AS m
LEFT JOIN
(
SELECT
--r.colloc, -- if you want to see r.colloc
v.TITLE,
v.DIRECTOR,
COUNT(v.TITLE) AS Rentnumber
FROM Video AS v
LEFT JOIN Rent as r on v.colloc = r.colloc
GROUP BY r.colloc, v.TITLE, v.DIRECTOR
) AS rs ON m.title = rs.title AND m.director = rs.director
Group by m.title, m.directorhttps://stackoverflow.com/questions/39587680
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