我的要求是在启动依赖作业之前等待两个线程完成执行。
为了做到这一点,我能够创建一个CountDownLatch和一个Waiter Thread,它将等待CountDownLatch变为零。一个约束是我不能使用主线程等待两个线程完成。主线程继续执行其他任务。
这东西确实有用。然而,我觉得在这方面的解决办法比坚实的设计。
我的问题如下:
我现在的代码是:
class Waiter implements Runnable {
private CountDownLatch latch;
Waiter (CountDownLatch latch){
this.latch = latch;
}
@Override
public void run() {
System.out.println("Waiter Started running..." + latch.getCount());
try {
latch.await();
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("Waiter ready to trigger Next Job!");
}
}
class Processor implements Runnable {
private CountDownLatch latch;
Processor (CountDownLatch latch){
this.latch = latch;
}
@Override
public void run() {
try {
Thread.sleep(300);
} catch (InterruptedException e) {
e.printStackTrace();
}
latch.countDown();
}
}
public class CountDownLatchDemo {
public static void main (String[] args) throws InterruptedException{
CountDownLatch latch = new CountDownLatch(2);
ExecutorService executor = Executors.newFixedThreadPool(2);
for (int i=0; i< 2; i++){
executor.submit(new Processor(latch));
}
ExecutorService waitExecutor = Executors.newFixedThreadPool(2);
waitExecutor.submit(new Waiter(latch));
Thread.sleep(3000);
executor.shutdown();
waitExecutor.shutdown();
System.out.println("Keep doing other things! Sleep here is just for help you run this code for test!");
}
}发布于 2016-09-17 17:44:05
CountDownLatch是适合您的任务的解决方案。但是Java 8提供了另一种选择- CompletableFuture。您可以为您的任务创建两个这样的未来,然后使用其中一个方法等待期货完成并异步执行其他内容。例如:
// Submit Task 1
CompletableFuture<Integer> f1 = CompletableFuture.supplyAsync(() -> {
try {
Thread.sleep(2000);
} catch (InterruptedException e) {
}
System.out.println("Task 1 completed");
return 5;
});
// Submit Task 2
CompletableFuture<Integer> f2 = CompletableFuture.supplyAsync(() -> {
try {
Thread.sleep(3000);
} catch (InterruptedException e) {
}
System.out.println("Task 2 completed");
return 7;
});
// This call will create a future that will wait for f1 and f2 to complete
// and then execute the runnable
CompletableFuture.allOf(f1, f2).thenRun(() -> {
System.out.println("Both completed");
});所有这些调用都将异步处理,您的主线程将继续运行。如果在第三个任务中需要前两个任务的结果,可以使用thenAcceptBothAsync()而不是allOf()
f1.thenAcceptBothAsync(f2, (a, b) -> System.out.println("Result = " + (a + b)));CompletableFuture中有许多方法允许您创建异步执行的任务链。JVM使用默认的ForkJoinPool来执行它们,但是您可以提供您自己的Executor来完成您的未来,并使用它们完成许多其他有用的事情。
https://stackoverflow.com/questions/39546565
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