我对Python非常陌生,我决定在不复制别人的代码的情况下,为自己设计一款石头、纸、剪刀游戏。不过,我需要一个毕多诺大人的帮助!
我在这里看到了摇滚,纸,剪刀的许多其他变体,但没有解释为什么我的版本不起作用。我的程序基本上遵循这样的格式:在开始时设置空变量,定义4个函数,打印简介文本,接收播放器输入,随机选择计算机的选择,然后评估它是赢了还是输了。
当玩家选择他们不想玩的游戏时,这个循环就会中断。(这一点工作得很好)
但是,每当我运行代码时,它总是给出抽签,并且似乎不为计算机的选择函数调用存储任何数据。有人知道我做错了什么吗?
非常感谢!
import random
playerAnswer = ''
computerAnswer = ''
winsTotal = 0
timesPlayed = 0
def showIntroText():
print('Time to play Rock, Paper, Scissors.')
print('Type in your choice below:')
def playerChoose():
playerInput = input()
return
def computerChoose():
randomNumber = random.randint(1, 3)
if randomNumber == 1:
computerPick = 'Paper'
elif randomNumber == 2:
computerPick = 'Scissors'
else:
computerPick = 'Rock'
return
def assessResult():
if playerAnswer == computerAnswer:
print('Draw!')
elif playerAnswer == 'Rock' and computerAnswer == 'Paper':
print('Paper beats Rock. You lose!')
elif playerAnswer == 'Paper' and computerAnswer == 'Scissors':
print('Scissors cuts Paper. You lose!')
elif playerAnswer == 'Scissors' and computerAnswer == 'Rock':
print('Rock blunts Scissors. You lose!')
else:
print('You win!')
winsTotal += 1
return
while True:
timesPlayed += 1
showIntroText()
playerAnswer = playerChoose()
computerAnswer = computerChoose()
assessResult()
print('Do you want to play again? (y/n)')
playAgain = input()
if playAgain == 'n':
break
print('Thank you for playing! You played ' + str(timesPlayed) + ' games.')发布于 2016-09-13 10:35:32
在大多数情况下,您忽略了返回值。
**在playerChoose()中添加“返回playerInput”,而不是只返回。
**在computerChoose()中添加‘返回computerPick’,而不是返回。
**在assessResult().中将winsTotal变量作为'winsTotal = 0‘使用之前初始化它
**在程序开始时,您已经初始化的变量超出了函数的范围。
请检查此StackOverFlow link以了解中变量的范围。
**在assessResult()中添加‘返回winsTotal’,而不是返回。
import random
def showIntroText():
print('Time to play Rock, Paper, Scissors.')
print('Type in your choice below:')
def playerChoose():
playerInput = input()
return playerInput
def computerChoose():
randomNumber = random.randint(1, 3)
if randomNumber == 1:
computerPick = 'Paper'
elif randomNumber == 2:
computerPick = 'Scissors'
else:
computerPick = 'Rock'
return computerPick
def assessResult(winsTotal):
if playerAnswer == computerAnswer:
print('Draw!')
elif playerAnswer == 'Rock' and computerAnswer == 'Paper':
print('Paper beats Rock. You lose!')
elif playerAnswer == 'Paper' and computerAnswer == 'Scissors':
print('Scissors cuts Paper. You lose!')
elif playerAnswer == 'Scissors' and computerAnswer == 'Rock':
print('Rock blunts Scissors. You lose!')
else:
print('You win!')
winsTotal += 1
return winsTotal
total_win = 0
while True:
timesPlayed += 1
showIntroText()
playerAnswer = playerChoose()
computerAnswer = computerChoose()
total_win = assessResult(total_win)
print('Do you want to play again? (y/n)')
playAgain = input()
if playAgain == 'n':
break
print('Thank you for playing! You played ' + str(timesPlayed) + ' games.' + 'Out of which you won '+ str(total_win))输出:
C:\Users\dinesh_pundkar\Desktop>python c.py
Time to play Rock, Paper, Scissors.
Type in your choice below:
"Rock"
You win!
Do you want to play again? (y/n)
"y"
Time to play Rock, Paper, Scissors.
Type in your choice below:
"Rock"
Draw!
Do you want to play again? (y/n)
"y"
Time to play Rock, Paper, Scissors.
Type in your choice below:
"Rock"
Paper beats Rock. You lose!
Do you want to play again? (y/n)
"y"
Time to play Rock, Paper, Scissors.
Type in your choice below:
"Rock"
Paper beats Rock. You lose!
Do you want to play again? (y/n)
"n"
Thank you for playing! You played 4 games.Out of which you won 1发布于 2016-09-13 10:37:55
这总是一个平局,因为您没有返回函数的答案,playerAnswer和computerAnswer都没有返回任何答案。
发布于 2016-09-13 10:43:03
在函数中添加输入和返回
def computerChoose和def assessResult不返回
例如,通过下面的代码,您可以玩这个游戏:
import random
playerAnswer = ''
computerAnswer = ''
winsTotal = 0
timesPlayed = 0
def playerChoose():
playerInput = input("insert:")
return playerInput
def computerChoose():
randomNumber = random.randint(1, 3)
if randomNumber == 1:
computerPick = 'Paper'
elif randomNumber == 2:
computerPick = 'Scissors'
else:
computerPick = 'Rock'
return computerPick
def assessResult(playerAnswer, computerAnswer):
if playerAnswer == computerAnswer:
print('Draw!')
elif playerAnswer == 'Rock' and computerAnswer == 'Paper':
print('Paper beats Rock. You lose!')
elif playerAnswer == 'Paper' and computerAnswer == 'Scissors':
print('Scissors cuts Paper. You lose!')
elif playerAnswer == 'Scissors' and computerAnswer == 'Rock':
print('Rock blunts Scissors. You lose!')
else:
print('You win!')
return
while True:
timesPlayed += 1
playerAnswer = playerChoose()
computerAnswer = computerChoose()
assessResult(playerAnswer,computerAnswer)
print('Do you want to play again? (y/n)')
playAgain = input()
if playAgain == 'n':
break
print('Thank you for playing! You played ' + str(timesPlayed) + ' games.')https://stackoverflow.com/questions/39467619
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