如何使用OpenXML设置Word文档中的发布日期

Question

在我的情况下，用户可以上传包含某些属性占位符的word文档(即，在upload中，用户已经插入> Quick > document并选择了一个属性)。我希望支持的特定属性是Title、Author、Company和Publish Date。

Title和Author设置为Package属性，Company设置为Extended属性。下面的代码设置了这些代码，这些代码正确地工作：

private static void SetDocumentProperties(ReportTemplateModel model, WordprocessingDocument wordDocument)
{
    //these properties always exist
    wordDocument.PackageProperties.Title = model.Title;
    wordDocument.PackageProperties.Creator = model.Author;
    wordDocument.PackageProperties.Created = DateTime.Now;
    wordDocument.PackageProperties.Modified = DateTime.Now;

    //these properties can be null
    if (wordDocument.ExtendedFilePropertiesPart == null)
    {
        wordDocument.AddNewPart<ExtendedFilePropertiesPart>();
    }
    if (wordDocument.ExtendedFilePropertiesPart.Properties == null)
    {
        wordDocument.ExtendedFilePropertiesPart.Properties = new Properties(new Company(model.SiteName));
    }
    else
    {
        wordDocument.ExtendedFilePropertiesPart.Properties.Company = new Company(model.SiteName);
    }
}

我的问题是，我无法确定如何设置Publish Date属性。我尝试使用下面的代码(从https://www.snip2code.com/Snippet/292005/WDSetCustomProperty中改编)将其添加为自定义文件属性，但这不起作用。我读过一些关于设置自定义属性的内容，但是我很困惑它们是如何工作的。我也不确定是否应该将Publish Date设置为自定义属性，还是其他类型的属性。

var customProps = wordDocument.CustomFilePropertiesPart;
if (customProps == null)
{
    customProps = wordDocument.AddCustomFilePropertiesPart();
    customProps.Properties = new DocumentFormat.OpenXml.CustomProperties.Properties();
}
var properties1 = new DocumentFormat.OpenXml.CustomProperties.Properties();

//I have tried both of these lines, neither worked.
//properties1.AddNamespaceDeclaration("op", "http://schemas.openxmlformats.org/officeDocument/2006/custom-properties");
properties1.AddNamespaceDeclaration("vt", "http://schemas.openxmlformats.org/officeDocument/2006/docPropsVTypes");

var customDocumentProperty1 = new DocumentFormat.OpenXml.CustomProperties.CustomDocumentProperty()
{
    FormatId = "{D5CDD505-2E9C-101B-9397-08002B2CF9AE}",
    PropertyId = 2,
    Name = "Publish Date"
};

customDocumentProperty1.Append(new DocumentFormat.OpenXml.VariantTypes.VTLPWSTR { Text = DateTime.Today.ToShortDateString() });

properties1.Append(customDocumentProperty1);

part.Properties = properties1;

应该将Publish Date设置为何种类型的属性，以及设置该属性的正确语法是什么？

更新：我发现Publish Date是一个可以使用下面的片段创建的CoverPageProperty，但是我仍然没有找到如何在文档中正确地设置它。

var coverPageProps = new DocumentFormat.OpenXml.Office.CoverPageProps.CoverPageProperties
{
    PublishDate = new PublishDate(DateTime.Today.ToShortDateString())
};

Answer 1

将下面的代码添加到我的SetDocumentProperties方法似乎是可行的。我必须承认我不完全理解下面的代码，所以任何解释都是欢迎的。此外，如果有一个解决方案不包括在C#中将XML作为字符串来编写，那么我更愿意避免这种情况。

const string publishDatePartId = "publishDatePart";

var publishDateXmlPart = wordDocument.MainDocumentPart.AddNewPart<CustomXmlPart>("application/xml", publishDatePartId);

var writer = new XmlTextWriter(publishDateXmlPart.GetStream(FileMode.Create), System.Text.Encoding.UTF8);

writer.WriteRaw($"<CoverPageProperties xmlns=\"http://schemas.microsoft.com/office/2006/coverPageProps\">" +
                $"<PublishDate>{DateTime.Today.ToShortDateString()}</PublishDate>" +
                $"</CoverPageProperties>");

writer.Flush();

writer.Close();

var customXmlPropertiesPart = publishDateXmlPart.AddNewPart<CustomXmlPropertiesPart>(publishDatePartId);

customXmlPropertiesPart.DataStoreItem = new DocumentFormat.OpenXml.CustomXmlDataProperties.DataStoreItem()
{
    //I don't know what this ID is, but it seems to somehow relate to the Publish Date
    ItemId = "{55AF091B-3C7A-41E3-B477-F2FDAA23CFDA}"
};