我现在在X3中将期望点添加到语法中。现在我违反了一条规则,看起来是这样的。
auto const id_string = +x3::char("A-Za-z0-9_);
auto const nested_identifier_def =
x3::lexeme[
*(id_string >> "::")
>> *(id_string >> ".")
>> id_string
];我想知道如何在这个规则中添加条件期望点。比如“如果有一个"::”然后跟着一个id_string“,或者”当有一个.时,就会跟着一个id_string“等等。对于这样的规则,我怎样才能做到这样的行为呢?
发布于 2016-08-20 14:33:49
我会按照你的意愿写出来:
auto const identifier
= lexeme [+char_("A-Za-z0-9_")];
auto const qualified_id
= identifier >> *("::" > identifier);
auto const simple_expression // only member expressions supported now
= qualified_id >> *('.' > identifier);与之对应的AST:
namespace AST {
using identifier = std::string;
struct qualified_id : std::vector<identifier> { using std::vector<identifier>::vector; };
struct simple_expression {
qualified_id lhs;
std::vector<identifier> rhs;
};
}现场演示
住在Coliru
#include <iostream>
#include <string>
#include <vector>
namespace AST {
using identifier = std::string;
struct qualified_id : std::vector<identifier> { using std::vector<identifier>::vector; };
struct simple_expression {
qualified_id lhs;
std::vector<identifier> rhs;
};
}
#include <boost/fusion/adapted.hpp>
BOOST_FUSION_ADAPT_STRUCT(AST::simple_expression, lhs, rhs)
#include <boost/spirit/home/x3.hpp>
namespace Parser {
using namespace boost::spirit::x3;
auto const identifier
= rule<struct identifier_, AST::identifier> {}
= lexeme [+char_("A-Za-z0-9_")];
auto const qualified_id
= rule<struct qualified_id_, AST::qualified_id> {}
= identifier >> *("::" > identifier);
auto const simple_expression // only member expressions supported now
= rule<struct simple_expression_, AST::simple_expression> {}
= qualified_id >> *('.' > identifier);
}
int main() {
using It = std::string::const_iterator;
for (std::string const input : { "foo", "foo::bar", "foo.member", "foo::bar.member.subobject" }) {
It f = input.begin(), l = input.end();
AST::simple_expression data;
bool ok = phrase_parse(f, l, Parser::simple_expression, boost::spirit::x3::space, data);
if (ok) {
std::cout << "Parse success: ";
for (auto& el : data.lhs) std::cout << "::" << el;
for (auto& el : data.rhs) std::cout << "." << el;
std::cout << "\n";
}
else {
std::cout << "Parse failure ('" << input << "')\n";
}
if (f != l)
std::cout << "Remaining unparsed input: '" << std::string(f, l) << "'\n";
}
}打印
Parse success: ::foo
Parse success: ::foo::bar
Parse success: ::foo.member
Parse success: ::foo::bar.member.subobjecthttps://stackoverflow.com/questions/39053814
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