我对Javascript的承诺相当陌生,在实现以下方面时遇到了问题:
var Promise = require('bluebird');
var jenkinsapi = require('jenkins-api');
var asyncJenkinsAPI = Promise.promisifyAll(jenkinsapi);
var jenkins = asyncJenkinsAPI.init("http://<user>:<password>@localhost:8080");
app.get('/api/servers', function(req, resp) {
SavedJob.find({})
.then(function(jobs) {
return Promise.all(jobs.map(function(job){
// do two calls with each job.name
// build new data with the result of the two calls
// return new data to next part of chain
var job_status = jenkins.job_info(job.name, function(err, jobData) { return jobData; });
var build_info = jenkins.last_build_info(job.name, function(err, buildData) { return buildData; });
return {task_name: job_status.name,
status: STATUSMAP[job_status.color] || "UNKNOWN",
latest_build:
{
build_date: build_info.timestamp,
build_status: build_info.result,
build_number: build_info.number,
build_url: build_info.url
}
};
}));
})
.then(function(results){
console.log(results);
});
});如何最好地实现在Promise.all()中使用每个job.name进行两个异步调用,并在最后得到一组结果?
发布于 2016-08-18 16:20:04
在对jenkins进行了改进之后,您将需要使用新的允诺返回方法:
var job_promise = jenkins.job_infoAsync(job.name);
var build_promise = jenkins.last_build_infoAsync(job.name);(您可能希望将{suffix: "_async"}作为更好的方法名称的promisifyAll传递)。
然后把这两个承诺结合起来,(Promise.all/Promise.props/Promise.join):
return Promise.join(job_promise, build_promise, function(job_status, build_info) {
return {
task_name: job_status.name,
status: STATUSMAP[job_status.color] || "UNKNOWN",
latest_build: {
build_date: build_info.timestamp,
build_status: build_info.result,
build_number: build_info.number,
build_url: build_info.url
}
};
});您的其余代码(映射、链接)运行良好。
https://stackoverflow.com/questions/39020938
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