我编写了一个tl解析器,现在可以使用最新的层(53)。但我不知道如何处理“旗子”类型。它们只在tl文档中提到,但在页面底部没有定义(据我所知):链接。
例如,当方法返回“消息”类型时,应该如下所示:message#c09be45f flags:# out:flags.1?true mentioned:flags.4?true media_unread:flags.5?true silent:flags.13?true post:flags.14?true id:int from_id:flags.8?int to_id:Peer fwd_from:flags.2?MessageFwdHeader via_bot_id:flags.11?int reply_to_msg_id:flags.3?int date:int message:string media:flags.9?MessageMedia reply_markup:flags.6?ReplyMarkup entities:flags.7?Vector<MessageEntity> views:flags.10?int edit_date:flags.15?int = Message;
如果我正确地理解了每个标志是在某个变量中设置的,对吗?
我的解析器将“message”类型分解如下:
id: -1063525281 params: name: flags type: name: out bit: 1 type: true name: mentioned bit: 4 type: true name: media\_unread bit: 5 type: true name: silent bit: 13 type: true name: post bit: 14 type: true name: from\_id bit: 8 type: int name: fwd\_from bit: 2 type: MessageFwdHeader name: via\_bot\_id bit: 11 type: int name: reply\_to\_msg\_id bit: 3 type: int name: media bit: 9 type: MessageMedia name: reply\_markup bit: 6 type: ReplyMarkup name: entities bit: 7 type: Vector<MessageEntity> name: views bit: 10 type: int name: edit\_date bit: 15 type: int name: id type: int name: to\_id type: Peer name: date type: int name: message type: string predicate: message type: Message
但是如果标志是某个变量中的位,那么是哪个变量呢?
相关: tl是基于一种正式的、标准化的语言规范,还是专门为电报创建的?我之所以这样问是因为如果它是一种正式语言的子集(比如yaml),那么最好使用已知的解析器来进行tl,而不是重新发明轮子。
发布于 2016-08-11 19:16:55
但是如果标志是某个变量中的位,那么是哪个变量呢?
Message#c09be45f flags:# out:flags.1?true mentioned:flags.4?true media_unread:flags.5?true silent:flags.13?true post:flags.14?true id:int from_id:flags.8?int to_id:Peer fwd_from:flags.2?MessageFwdHeader via_bot_id:flags.11?int reply_to_msg_id:flags.3?int date:int message:string media:flags.9?MessageMedia reply_markup:flags.6?ReplyMarkup entities:flags.7?Vector<MessageEntity> views:flags.10?int edit_date:flags.15?int = Message;示例:flags:# out:flags.1?true
解码标志:BinaryAND(标志,2^ix) === 2^ix ->这将帮助您确定是否包含字段
标志=值如果是flags字段,这通常是带有标志的对象的第一个字段
==标志索引,这是一个表示标志位置的数字,例如,这里的out:flags.1?true是标志位置1中的字段,类型为真
对于上面的示例,如果不是out,则true的值为BAND(flags,2^N) == 2^N,则忽略out字段。
代码-消息编码(Elixir)
def encode(%Message{} = x), do: <<95, 228, 155, 192, encode(:Int, x.flags)::binary, enc_f(:True, x.out, x.flags, 2)::binary, enc_f(:True, x.mentioned, x.flags, 16)::binary, enc_f(:True, x.media_unread, x.flags, 32)::binary, enc_f(:True, x.silent, x.flags, 8192)::binary, enc_f(:True, x.post, x.flags, 16384)::binary, encode(:Int, x.id)::binary, enc_f(:Int, x.from_id, x.flags, 256)::binary, encode(x.to_id)::binary, enc_f(x.fwd_from, x.flags, 4)::binary, enc_f(:Int, x.via_bot_id, x.flags, 2048)::binary, enc_f(:Int, x.reply_to_msg_id, x.flags, 8)::binary, encode(:Int, x.date)::binary, encode(:String, x.message)::binary, enc_f(x.media, x.flags, 512)::binary, enc_f(x.reply_markup, x.flags, 64)::binary, enc_vf(x.entities, x.flags, 128)::binary, enc_f(:Int, x.views, x.flags, 1024)::binary, enc_f(:Int, x.edit_date, x.flags, 32768)::binary>>代码-消息解码(Elixir)
def decode(<<95, 228, 155, 192, bin::binary>>) do
{flags, bin} = decode(:Int, bin)
{out, bin} = decode(:True, bin, flags, 2) # 1
{mentioned, bin} = decode(:True, bin, flags, 16) # 4
{media_unread, bin} = decode(:True, bin, flags, 32) # 5
{silent, bin} = decode(:True, bin, flags, 8192) # 13
{post, bin} = decode(:True, bin, flags, 16384) # 14
{id, bin} = decode(:Int, bin)
{from_id, bin} = decode(:Int, bin, flags, 256) # 8
{to_id, bin} = decode(bin)
{fwd_from, bin} = decode(bin, flags, 4) # 2
{via_bot_id, bin} = decode(:Int, bin, flags, 2048) # 11
{reply_to_msg_id, bin} = decode(:Int, bin, flags, 8) # 3
{date, bin} = decode(:Int, bin)
{message, bin} = decode(:String, bin)
{media, bin} = decode(bin, flags, 512) # 9
{reply_markup, bin} = decode(bin, flags, 64) # 6
{entities, bin} = decode([:MessageEntity], bin, flags, 128) # 7
{views, bin} = decode(:Int, bin, flags, 1024) # 10
{edit_date, bin} = decode(:Int, bin, flags, 32768) # 15
{%Message{flags: flags, out: out, mentioned: mentioned, media_unread: media_unread, silent: silent, post: post, id: id, from_id: from_id, to_id: to_id, fwd_from: fwd_from, via_bot_id: via_bot_id, reply_to_msg_id: reply_to_msg_id, date: date, message: message, media: media, reply_markup: reply_markup, entities: entities, views: views, edit_date: edit_date}, bin}
end
#5 == 2^5 == 32
#4 == 2^4 == 16所以基本上是N == 2^N, where N == ix
https://stackoverflow.com/questions/38903321
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