问题
我需要从数据库中返回最短和最长的城市名称以及它们各自的长度。我还欢迎对此查询进行改进,以使其更加优雅。
SQL Fiddle
到目前为止,我有一个示例数据库&查询:http://sqlfiddle.com/#!9/3b4a7c/1/0
查询
SELECT DISTINCT City, LENGTH(City) as len
FROM STATION
WHERE LENGTH(City)=(SELECT MIN(LENGTH(City)) FROM STATION)
OR LENGTH(City)=(SELECT MAX(LENGTH(City)) FROM STATION)
ORDER BY len当前结果
Dole 4
Reus 4
Sant'Egidio del Monte Albino 28期望结果
Dole 4
Sant'Egidio del Monte Albino 28发布于 2016-08-01 00:33:25
我会使用union all、order by和limit来完成这个任务。。。如果您只想要一个最长和最短的名称的例子:
(select city, length(city)
from station
order by length(city) asc
limit 1
) union all
(select city, length(city)
from station
order by length(city) desc
limit 1
);如果你想打领带,当不止一个城市比赛的时候,我会:
select s.city, length(s.city)
from station s cross join
(select max(length(city)) as maxl, min(length(city)) as minl
from station
) ss
where length(s.city) in (ss.minl, ss.maxl);发布于 2016-08-01 00:41:03
select min(a.city),length(a.city)
from station a
join (SELECT min(length(city)) minlength,max(length(city)) maxlength from station) b
on length(a.city) in (minlength,maxlength)
group by length(a.city)https://stackoverflow.com/questions/38689560
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