
我在这里看到了
我想尝试的是让v_total_project看起来像那样。我已经试过这个代码了
select o.id_project AS id_project,
sum((o.office_expense + m.misc_expense)) AS total_expense
from v_office_project o inner join v_misc_project m on o.id_project = m.id_project
group by o.id_project, m.id_project我知道我的代码不会打印v_misc_project.id_project。因此,我尝试联合打印两个id_project,并得到错误不同的列数。
select o.id_project AS id_project
from v_office_project o
union
select m.id_project as id_project,
sum((o.office_expense + m.misc_expense)) AS total_expense
from v_office_project o inner join v_misc_project m on o.id_project = m.id_project
group by id_project还有别的办法吗?提前谢谢你,
发布于 2016-07-27 05:52:31
SELECT
o.id_project AS id_project,
sum(
o.office_expense + ifnull(m.misc_expense, 0)
) AS total_expense
FROM
v_office_project o
LEFT JOIN v_misc_project m ON o.id_project = m.id_project
GROUP BY
id_project
UNION
SELECT
m.id_project AS id_project,
sum(
ifnull(o.office_expense, 0) + m.misc_expense
) AS total_expense
FROM
v_office_project o
RIGHT JOIN v_misc_project m ON o.id_project = m.id_project
GROUP BY
id_project在你的工会的第一次选择中,你失去了支付开支的机会。
另外,连接也丢失了,添加了它。而不是INNER JOIN,而是使用LEFT或RIGHT Join,否则您只能得到两个表中的id_project的结果。
在计算中添加了ifnull(),因为LEFT / RIGHT联接可以返回null,而null必须被视为0。
https://stackoverflow.com/questions/38604133
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