TypeError:对于include()，视图必须是可调用的或列表/元组。

Question

我是django和python的新手。在将url映射到视图期间，我得到以下错误:在TypeError()的情况下，视图必须是可调用的或列表/元组。

Urls。py代码：-

from django.conf.urls import url
from django.contrib import admin


urlpatterns = [
    url(r'^admin/', admin.site.urls),
    url(r'^posts/$', "posts.views.post_home"), #posts is module and post_home 
]                                              # is a function in view. 

views.py代码：-

from django.shortcuts import render
from django.http import HttpResponse
# Create your views here.
#function based views

def post_home(request):
    response = "<h1>Success</h1>"
    return HttpResponse(response)

溯源

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Answer 1

在1.10中，您不能再将导入路径传递给url()，您需要传递实际的视图函数：

from posts.views import post_home

urlpatterns = [
    ...
    url(r'^posts/$', post_home),
]        

Answer 2

将您的管理url模式替换为

url(r'^admin/', include(admin.site.urls))

所以你的urls.py变成：

from django.conf.urls import url, include
from django.contrib import admin


urlpatterns = [
    url(r'^admin/', include(admin.site.urls)),
    url(r'^posts/$', "posts.views.post_home"), #posts is module and post_home 
] 

通过include (在1.9之前)可以调用管理urls。

Answer 3

代表Django 1.11.2

在主urls.py中写：

from django.conf.urls import include,url
from django.contrib import admin

urlpatterns = [
    url(r'^admin/', admin.site.urls),
    url(r'^posts/', include("Post.urls")),
] 

并在appname/urls.py文件中写入：

from django.conf.urls import url
from . import views

urlpatterns = [
    url(r'^$',views.post_home),
]