我正在尝试将下面的curl代码转换为pycurl。我不想使用请求。我需要使用pycurl,因为请求在我的旧python版本中不能完全工作。
curl
-X POST
-H "Accept-Language: en"
-F "images_file=@fruitbowl.jpg"
-F "parameters=@myparams.json"
"https://gateway-a.watsonplatform.net/visual-recognition/api/v3/classify?api_key={api-key}&version=2016-05-20"有人能告诉我如何用PyCurl写出来吗?
发布于 2016-07-15 10:55:12
import pycurl
c = pycurl.Curl()
c.setopt(c.URL, 'https://gateway-a.watsonplatform.net/visual-recognition/api/v3/classify?api_key={api-key}&version=2016-05-20')
c.setopt(c.POST, 1)
c.setopt(c.HTTPPOST, [("images_file", (c.FORM_FILE, "fruitbowl.jpg"))])
c.setopt(c.HTTPPOST, [("parameters", (c.FORM_FILE, "myparams.json"))])
c.setopt(pycurl.HTTPHEADER, ['Accept-Language: en'])
c.perform()
c.close()https://stackoverflow.com/questions/38393830
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