登录注册系统
登录注册系统
提问于 2016-07-14 14:21:17
我的登录和注册系统有一个小问题，但我不知道问题在哪里。当我按“登录”或“注册”时，下一页是白色的。我只看到我的留言：“再试一次！”我创建了3个PHP文件：
1) index.php
<!DOCTYPE html>
<html>
<head>
</head>
<body>
<form action="logreg.php" metodh="post" accept-charset="utf-8">
<label>Username:</label><input type="text" name="username" placeholder="Username">
<br>
<label>Password:</label><input type="password" name="password" placeholder="Password">
<br>
<input type="submit" name="login" value="Login">
<input type="submit" name="register" value="Register">
</form>
</body>
</html>
我认为问题在下一个文件中：
2) logreg.php
<?php
$servername = "localhost";
$username = "alex";
$password = "calamar28";
$database = "register/login";
$conn = mysqli_connect($servername, $username, $password, $database );
if(!$conn){
die("Connection failde:".mysqli_connect_error());
}
if(isset($_POST["login"])) {
$user = $_POST['username'];
$pass = $_POST['password'];
$sql = "SELECT * FROM users WHERE username='$user' AND password='$pass';";
$result = mysqli_query($conn, $sql);
$count = mysqli_num_rows($result);
if ($count == 1)
{
header("Location: personal.php");
}
else
{
echo "Username or password is incorrect!";
}
}
else if(isset($_POST["register"])) {
$user = $_POST['username'];
$pass = $_POST['password'];
$sql = "INSERT INTO users (id, username, password) VALUES ('', '$user', '$pass')";
$result = mysqli_query($conn, $sql);
}
else
{
echo "Try again!";
}
?>
3) personal.php
<?php
if(isset($_POST["login"])){
echo "Welcome to you personal area !";
echo '<a href = "proiect4.php">Your proiect</a>';
}
else
{
echo "You are not logged in!";
}
?>
回答 2
Stack Overflow用户
回答已采纳
发布于 2016-07-14 14:48:19
您还需要设置一些会话变量才能传递到personal.php页面.这将有助于确定用户是否已成功登录，因为当您重定向到此页面时，原始发布的数据将无法传输.您将希望您的logreg.php如下所示：
<?php
if (!isset($_SESSION)) {session_start();}
$servername = "localhost";
$username = "alex";
$password = "calamar28";
$database = "register/login";
$conn = mysqli_connect($servername, $username, $password, $database );
if(!$conn){
die("Connection failde:".mysqli_connect_error());
}
if(isset($_POST["login"])) {
$user = $_POST['username'];
$pass = $_POST['password'];
$sql = "SELECT * FROM users WHERE username='$user' AND password='$pass';";
$result = mysqli_query($conn, $sql);
$count = mysqli_num_rows($result);
if ($count == 1)
{
$_SESSION['loggedIn'] = 1;
header("Location: personal.php");
}
else
{
echo "Username or password is incorrect!";
}
}
else if(isset($_POST["register"])) {
$user = $_POST['username'];
$pass = $_POST['password'];
$sql = "INSERT INTO users (id, username, password) VALUES ('', '$user', '$pass')";
$result = mysqli_query($conn, $sql);
}
else
{
echo "Try again!";
}
?>
然后，您的personal.php页面将更改为：
<?php
if (!isset($_SESSION)) {session_start();}
if(isset($_SESSION["loggedIn"]) && ($_SESSION["loggedIn"] == 1) ){
echo "Welcome to you personal area !";
echo '<a href = "proiect4.php">Your proiect</a>';
}
else
{
echo "You are not logged in!";
}
?>
Stack Overflow用户
发布于 2016-07-14 14:31:32
HTML的默认方法是GET。在HTML中，您编写了metodh，而不是方法。这将被忽略，然后您的方法将自动默认为GET。除此之外，PHP代码也不错。将HTML代码更改为如下所示，所有内容都应如预期的那样正常工作：
<!DOCTYPE html>
<html>
<head>
</head>
<body>
<form action="logreg.php" method="post" accept-charset="utf-8">
<label>Username:</label><input type="text" name="username" placeholder="Username">
<br>
<label>Password:</label><input type="password" name="password" placeholder="Password">
<br>
<input type="submit" name="login" value="Login">
<input type="submit" name="register" value="Register">
</form>
</body>
</html>页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/38376750
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