Cython中的AES-NI本质？

Question

在Cython代码中有使用AES-NI指令的方法吗？

我能找到的最接近的是有人如何访问SIMD指令：GnOOsLuQJ

未回答Python线程中的AES-NI：Python support for AES-NI

Answer 1

您应该能够像定义Cython中的普通C函数一样定义本质。有点像

cdef extern from "emmintrin.h": # I'm going off the microsoft documentation for where the headers are
    # define the datatype as an opaque type
    ctypedef struct __m128i:
        pass

    __m128i _mm_set_epi32 (int i3, int i2, int i1, int i0)

cdef extern from "wmmintrin.h":
    __m128i _mm_aesdec_si128(__m128i v,__m128i rkey)

# then in some Cython function
def f():
   cdef __m128i v = _mm_set_epi32(1,2,3,4)
   cdef __m128i key = _mm_set_epi32(5,6,7,8)
   cdef __m128i result = _mm_aesdec_si128(v,key)

“如何将其应用于bytes数组”这个问题？首先，得到字节数组的char*。然后，只需使用range来迭代它(小心不要跑出终点)。

# assuming you already have an __m128i key
cdef __m128i v
cdef char* array = python_bytes_array # auto conversion
cdef int i, j

# you NEED to ensure that the byte array has a length divisible by
# 16, otherwise you'll probably get a segmentation fault.
for i in range(0,len(python_bytes_array),16):
    # go over in chunks of 16
    v = _mm_set_epi8(array[i+15],array[i+14],array[i+13],
            # etc... fill in the rest 
            array[i+1], array[i])

    cdef __m128 result = _mm_aesdec_si128(v,key)

    # write back to the same place?
    for j in range(16):
        array[i+j] = _mm_extract_epi8(result,j)