是否有机会提高以下查询的速度:
select distinct
a.InvoiceAcc,
(select top 1 b.CustomerName
from dbo.tblsales as b
where b.InvoiceAcc = a.InvoiceAcc),
(select sum(b.SalesValue)
from dbo.tblsales as b
where b.InvoiceAcc = a.InvoiceAcc and b.Month = '2016-1') as [01],
(select sum(b.SalesValue)
from dbo.tblsales as b
where b.InvoiceAcc = a.InvoiceAcc and b.Month = '2016-2') as [02],
(select sum(b.SalesValue)
from dbo.tblsales as b
where b.InvoiceAcc = a.InvoiceAcc and b.Month = '2016-3') as [03],
(select sum(b.SalesValue)
from dbo.tblsales as b
where b.InvoiceAcc = a.InvoiceAcc and b.Month = '2016-4') as [04],
(select sum(b.SalesValue)
from dbo.tblsales as b
where b.InvoiceAcc = a.InvoiceAcc and b.Month = '2016-5') as [05],
(select sum(b.SalesValue) from dbo.tblsales as b where b.InvoiceAcc = a.InvoiceAcc and b.Month = '2016-6') as [06],
(select sum(b.SalesValue) from dbo.tblsales as b where b.InvoiceAcc = a.InvoiceAcc and b.Month = '2016-7') as [07],
(select sum(b.SalesValue) from dbo.tblsales as b where b.InvoiceAcc = a.InvoiceAcc and b.Month = '2016-8') as [08],
(select sum(b.SalesValue) from dbo.tblsales as b where b.InvoiceAcc = a.InvoiceAcc and b.Month = '2016-9') as [09],
(select sum(b.SalesValue) from dbo.tblsales as b where b.InvoiceAcc = a.InvoiceAcc and b.Month = '2016-10') as [10],
(select sum(b.SalesValue) from dbo.tblsales as b where b.InvoiceAcc = a.InvoiceAcc and b.Month = '2016-11') as [11],
(select sum(b.SalesValue) from dbo.tblsales as b where b.InvoiceAcc = a.InvoiceAcc and b.Month = '2016-12') as [12]
from
dbo.tblsales as a
group by
a.InvoiceAcc, CustomerName如果将params月发送为2016和InvoiceAcc (不需要),那么Server中的视图是什么?
非常感谢。
发布于 2016-07-08 17:59:27
根据你的例子你想要这样
select
InvoiceAcc,
CustomerName,
sum(CASE WHEN [Month] = '2016-1' then salesvalue else 0 end) as [01],
sum(CASE WHEN [Month] = '2016-2' then salesvalue else 0 end) as [02],
sum(CASE WHEN [Month] = '2016-3' then salesvalue else 0 end) as [03],
sum(CASE WHEN [Month] = '2016-4' then salesvalue else 0 end) as [04],
sum(CASE WHEN [Month] = '2016-5' then salesvalue else 0 end) as [05],
sum(CASE WHEN [Month] = '2016-6' then salesvalue else 0 end) as [06],
sum(CASE WHEN [Month] = '2016-7' then salesvalue else 0 end) as [07],
sum(CASE WHEN [Month] = '2016-8' then salesvalue else 0 end) as [08],
sum(CASE WHEN [Month] = '2016-9' then salesvalue else 0 end) as [09],
sum(CASE WHEN [Month] = '2016-10' then salesvalue else 0 end) as [10],
sum(CASE WHEN [Month] = '2016-11' then salesvalue else 0 end) as [11],
sum(CASE WHEN [Month] = '2016-12' then salesvalue else 0 end) as [12]
from dbo.tblsales
group by InvoiceAcc, CustomerName我确实觉得这个测试(如Month = '2016-1')很奇怪--我希望有一个日期字段和一个类似MONTH(invoiceDate) = 1的测试。
我还认为,在sql中使用distinct通常是一个糟糕的查询的指示--从设计良好的模型中正确设计的查询很少需要不同。
如果要删除其他名称,最好的方法是:
select
InvoiceAcc,
CustomerName,
sum(CASE WHEN [Month] = '2016-1' then salesvalue else 0 end) as [01],
sum(CASE WHEN [Month] = '2016-2' then salesvalue else 0 end) as [02],
sum(CASE WHEN [Month] = '2016-3' then salesvalue else 0 end) as [03],
sum(CASE WHEN [Month] = '2016-4' then salesvalue else 0 end) as [04],
sum(CASE WHEN [Month] = '2016-5' then salesvalue else 0 end) as [05],
sum(CASE WHEN [Month] = '2016-6' then salesvalue else 0 end) as [06],
sum(CASE WHEN [Month] = '2016-7' then salesvalue else 0 end) as [07],
sum(CASE WHEN [Month] = '2016-8' then salesvalue else 0 end) as [08],
sum(CASE WHEN [Month] = '2016-9' then salesvalue else 0 end) as [09],
sum(CASE WHEN [Month] = '2016-10' then salesvalue else 0 end) as [10],
sum(CASE WHEN [Month] = '2016-11' then salesvalue else 0 end) as [11],
sum(CASE WHEN [Month] = '2016-12' then salesvalue else 0 end) as [12]
from (
SELECT InvoiceAcc, CustomerName, Month, salesvalue,
ROW_NUMBER() OVER (PARTITION BY InvoiceAcc ORDER BY CustomerName) AS RN
FROM tblsales
) x
WHERE RN=1
group by InvoiceAcc, CustomerName发布于 2016-07-08 19:04:26
你可以试着用枢轴
select
InvoiceAcc,
CustomerName,
[2016-1] as [01],
[2016-2] as [02],
[2016-3] as [03],
[2016-4] as [04],
[2016-5] as [05],
[2016-6] as [06],
[2016-7] as [07],
[2016-8] as [08],
[2016-9] as [09],
[2016-10] as [10],
[2016-11] as [11],
[2016-12] as [12]
from (
select
InvoiceAcc,
CustomerName,
[Month],
sum(SalesValue) SalesValue
from dbo.tblsales
group by InvoiceAcc, CustomerName,[Month]) tb
pivot
(
sum(SalesValue)
for [Month] in ([2016-1],[2016-2] ,[2016-3],[2016-4],[2016-5],[2016-6],[2016-7],[2016-8],[2016-9],[2016-10],[2016-11],[2016-12])
) pvthttps://stackoverflow.com/questions/38272739
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