有没有办法将设置从JsonSerializer类中取出并在新的JsonSerializer中重新实现?
似乎没有任何方法来做这样的事情。我发现最好的方法是通过反射调用私有方法,ApplySerializerSettings。
我正在尝试从WriteJson方法中获取序列化程序,并将其复制到一个新的序列化程序中,对其进行一些调整。具体来说,我想替换ContractResolver。
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)发布于 2016-07-06 17:39:35
似乎最好的方法就是把所有的设置复制到一个新的对象中。有很多这样的工具,所以这里有一个很好的扩展方法可以使用(从8.0.3开始)。
public static class JsonSerializerExtensions
{
public static JsonSerializer DeepCopy(this JsonSerializer serializer)
{
var copiedSerializer = new JsonSerializer
{
Context = serializer.Context,
Culture = serializer.Culture,
ContractResolver = serializer.ContractResolver,
ConstructorHandling = serializer.ConstructorHandling,
CheckAdditionalContent = serializer.CheckAdditionalContent,
DateFormatHandling = serializer.DateFormatHandling,
DateFormatString = serializer.DateFormatString,
DateParseHandling = serializer.DateParseHandling,
DateTimeZoneHandling = serializer.DateTimeZoneHandling,
DefaultValueHandling = serializer.DefaultValueHandling,
EqualityComparer = serializer.EqualityComparer,
FloatFormatHandling = serializer.FloatFormatHandling,
Formatting = serializer.Formatting,
FloatParseHandling = serializer.FloatParseHandling,
MaxDepth = serializer.MaxDepth,
MetadataPropertyHandling = serializer.MetadataPropertyHandling,
MissingMemberHandling = serializer.MissingMemberHandling,
NullValueHandling = serializer.NullValueHandling,
ObjectCreationHandling = serializer.ObjectCreationHandling,
PreserveReferencesHandling = serializer.PreserveReferencesHandling,
ReferenceResolver = serializer.ReferenceResolver,
ReferenceLoopHandling = serializer.ReferenceLoopHandling,
StringEscapeHandling = serializer.StringEscapeHandling,
TraceWriter = serializer.TraceWriter,
TypeNameHandling = serializer.TypeNameHandling,
SerializationBinder = serializer.SerializationBinder,
TypeNameAssemblyFormatHandling = serializer.TypeNameAssemblyFormatHandling
};
foreach (var converter in serializer.Converters)
{
copiedSerializer.Converters.Add(converter);
}
return copiedSerializer;
}
}它很难看,但至少你只需要写一次。要稍微小心,因为属性本身并不是很深的复制。
下面的答案是片状的,取决于您的实现,特别是在解决契约时。留着以防它对别人有帮助。
所以,我不能完全复制设置,但我发现了一个很好的工作,可能需要考虑。您可以简单地在锁定的上下文中设置要更改的属性,然后在之后重置它们。
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
var thing = value as IThing;
if (thing == null)
throw new ArgumentException($"Writing Json failed because " +
"value was not a 'Thing' of type, {typeof(IThing).FullName}");
JObject jsonThing;
//If your solution is multithreaded,
//and is using a shared serializer (which you probably are),
//you should lock the serializer so that it doesn't accidentally use
//the "CustomObjectResolver"
lock (serializer)
{
//Hold the original value(s) to reset later
var originalContractResolver = serializer.ContractResolver;
//Set custom value(s)
serializer.ContractResolver = new CustomObjectResolver();
//Serialization with custom properties
jsonThing = JObject.FromObject(value, serializer);
//Reset original value(s)
serializer.ContractResolver = originalContractResolver;
}
//Finish serializing and write to writer.
}发布于 2018-10-08 19:11:03
不确定这是否是主题,但由于这是在我的谷歌搜索克隆JSONSerializerSettings时出现的第一条帖子,我想我会留下一个通知。
我刚才也有一个类似的要求。
在我的.Net核心WebApi解决方案中,我们使用默认的方法来序列化JSON
jsonSerializaerSettings.NullValueHandling = NullValueHandling.Ignore;但是在几个端点中,我也想序列化空属性,因为这些端点代表一个数据集。因此,在序列化时,所有对象都应该具有所有属性。
我尝试了几种方法,然后阅读了选项模式,偶然发现了IOptionSnapshot - https://learn.microsoft.com/en-us/aspnet/core/fundamentals/configuration/options?view=aspnetcore-2.1#reload-configuration-data-with-ioptionssnapshot。
因此,我最终将一个IOptionsSnapshot注入到我的控制器方法中,这给了我一个默认选项的副本,我可以对这个请求进行修改和使用。
在下一个请求中,注入的选项将恢复为默认选项。
很好,很容易-至少是为了我的目的。
所以我的样本的最后一个解决方案是这样的
[HttpPost("dataset", Name = "GetReportDataset")]
public IActionResult GetReportDataset(
[FromServices]IOptionsSnapshot<MvcJsonOptions> jsonOptions,
[FromBody]DataSetReport report,
[FromQuery]int? top)
{
//Logic to fetch dataset
var myDataSet = myRepository.GetDataset(report, top);
var serializerSettings = jsonOptions.Value.SerializerSettings;
serializerSettings.NullValueHandling = NullValueHandling.Include;
return new JsonResult(myDataSet, serializerSettings);
}希望这能帮助其他人来这里进行类似的使用。
/Anders
https://stackoverflow.com/questions/38230326
复制相似问题