我希望通过将xmonad.hs通过stack迁移到它自己的沙箱项目环境中来扩展它。事实证明,通过将xmonad main函数嵌入到利用xmonad-entryhelper的父main中,这种沙箱是可能的。按照项目自述中的说明,将xmonad.hs转换为:
main :: IO ()
main = do
statBar <- spawnPipe myXMobar
xmonad def
{ terminal = myTerminal
, focusFollowsMouse = myFocusFollowsMouse
, borderWidth = myBorderWidth
, modMask = myModMask
, workspaces = myWorkspaces
, normalBorderColor = myNormalBorderColor
, focusedBorderColor = myFocusedBorderColor
-- key bindings
, keys = myKeys
--, mouseBindings = myMouseBindings
-- hooks, layouts
, layoutHook = myLayoutHook
, manageHook = manageHook def <+> myManageHook
--, handleEventHook = myEventHook
, logHook = myLogHook statBar >> setWMName "LG3D"
--, startupHook = myStartupHook
}为了..。
kaleidoscope :: IO ()
kaleidoscope = do
statBar <- spawnPipe myXMobar
xmonad def
{ terminal = myTerminal
, focusFollowsMouse = myFocusFollowsMouse
, borderWidth = myBorderWidth
, modMask = myModMask
, workspaces = myWorkspaces
, normalBorderColor = myNormalBorderColor
, focusedBorderColor = myFocusedBorderColor
-- key bindings
, keys = myKeys
--, mouseBindings = myMouseBindings
-- hooks, layouts
, layoutHook = myLayoutHook
, manageHook = manageHook def <+> myManageHook
--, handleEventHook = myEventHook
, logHook = myLogHook statBar >> setWMName "LG3D"
--, startupHook = myStartupHook
}
main :: IO ()
main = EH.withCustomHelper kaleidoscopeConfig
where
kaleidoscopeConfig = EH.defaultConfig
{ EH.run = kaleidoscope
, EH.compile = \force -> EH.withLock ExitSuccess $ do
let cmd =
if force
then "cd /home/oldmanmike/src/github.com/oldmanmike/kaleidoscope && stack clean && stack build"
else "cd /home/oldmanmike/src/github.com/oldmanmike/kaleidoscope && stack build"
EH.compileUsingShell cmd
, EH.postCompile = EH.defaultPostCompile
}因此,我现在可以使用xmonad --recompile编译我的项目,在.xmonad中找到的二进制文件可以软链接到我的沙箱项目生成的二进制文件。
但由于某种原因,xmonad --restart 不再工作了。是什么把它绊倒了?
该命令本身似乎没有从X产生任何错误-它只是成功地返回,甚至没有任何迹象发生任何事情。我尝试在shell上使用xmonad --restart命令,并将xmonad中的mod-q绑定到spawnPipe "xmonad --restart"或io sendRestart --两者都不起作用。当我关闭我的Xserver并手动重新启动它时,就会出现任何和所有的更新,但是现在热交换更改似乎不起作用。它需要同时看到两个独立的双生子吗?当前的双生子和新的?
编辑:我一直在通过阅读xmonad、xmonad-entryhelper和X11的源代码来处理这个问题。我现在把这个拆开:
sendRestart :: IO ()
sendRestart = do
dpy <- openDisplay ""
rw <- rootWindow dpy $ defaultScreen dpy
xmonad_restart <- internAtom dpy "XMONAD_RESTART" False
allocaXEvent $ \e -> do
setEventType e clientMessage
setClientMessageEvent e rw xmonad_restart 32 0 currentTime
sendEvent dpy rw False structureNotifyMask e
sync dpy False我还不熟悉X11 API,但奇怪的是internAtom函数以及XMONAD_RESTART在客户端消息中的用途。还有一个处理程序:
handle e@ClientMessageEvent { ev_message_type = mt } = do
a <- getAtom "XMONAD_RESTART"
if (mt == a)
then restart "xmonad" True
else broadcastMessage e
handle e = broadcastMessage e -- trace (eventName e) -- ignoring所以我猜原子只是用来标识消息事件的特殊字符串?当我运行重新启动时,我不会收到任何错误消息,因此它似乎使它一直到操作句柄:
restart :: String -> Bool -> X ()
restart prog resume = do
broadcastMessage ReleaseResources
io . flush =<< asks display
let wsData = show . W.mapLayout show . windowset
maybeShow (t, Right (PersistentExtension ext)) = Just (t, show ext)
maybeShow (t, Left str) = Just (t, str)
maybeShow _ = Nothing
extState = return . show . catMaybes . map maybeShow . M.toList . extensibleState
args <- if resume then gets (\s -> "--resume":wsData s:extState s) else return []
catchIO (executeFile prog True args Nothing)我怀疑xmonad-x86_64-linux在xmonad的系统安装中编译和启动时有一个权限问题,而不是我的沙箱(目前与堆栈生成的二进制文件有符号链接)。
发布于 2016-06-29 20:55:56
事实证明,问题是我不能使用堆栈生成的xmonad二进制文件,即使它在我的路径中,而且~/.xmonad/xmonad-x86_64-linux也是与它相关联的。相反,我通过将mod绑定到以下内容来重新开始工作:
restart "/home/oldmanmike/.xmonad/xmonad-x86_64-linux" True只要我给它绝对的路径,它就能工作。
考虑到在前面的观察中,在我的.xinitrc中放置以下内容会导致X崩溃,这是有意义的:
exec xmonad相反,我不得不在最初的发布中使用以下内容:
exec ~/.xmonad/xmonad-x86_64-linux因此,现在看来,调用xmonad对于命令来说不太可靠,我应该将xmonad-x86_64-linux路径化名,并从现在起调用它。
https://stackoverflow.com/questions/38102625
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