git包:本地和远程回购之间的双向所有分支同步。

Question

机器A有互联网连接，而机器B没有。两者都有本地存储库，而机器A可以与Github交互。发展发生在这两台机器上。git-bundle被用来保持存储库的同步。

通常的同步流：

1. 创建B中所有分支的一个包，并将其转移到A。
2. 在A上克隆github存储库，将所有分支从包中拉到从github克隆的存储库中。将更新的存储库(所有分支)推送到github。
3. 从github存储库创建所有分支的包。将包转移到B。将所有分支从包中拉到B上的存储库中。

有一种方法可以创建存储库的所有分支。但是，是否有一种方法可以同时将一个包的所有分支拉到本地存储库中呢？

在单分支存储库情况下，双向同步似乎是直接的。

Answer 1

由于捆绑与任何其他存储库一样-唯一的区别是一个包碰巧存储为一个文件-您可以使用git pull --all从包中获取所有分支并将它们合并到相应的跟踪分支中：

git pull --all /path/to/bundle

但是，请注意，--all选项仅适用于git fetch。这意味着只有当前的本地分支(即HEAD引用的分支)将被更新。如果您还想更新所有本地分支，您必须自己为它编写一个脚本，或者使用类似于盖特-的内容。

Answer 2

向您的~/.gitconfig中添加以下pllbundle支git别名，然后运行git pullbundlebranches ../[filename].gitbundle。

[alias]
  pullbundlebranches = "!f() { git pull --tags $1; git fetch $1; git bundle verify $1 | grep ' refs/heads/' | (while read line; do \
    commit=`echo $line | cut -d' ' -f1`; branch=`echo $line | sed 's_[^\\ ]*\\ refs/heads/__'`; \
    if git show-ref -q --heads $branch; then \
      old_commit=`git rev-parse $branch`; \
      if [ \"$old_commit\" = \"$commit\" ]; then \
        echo 'Skipping' $branch 'which is up-to-date at' $old_commit; \
      elif git merge-base --is-ancestor $branch $commit; then \
        current_branch=`git rev-parse --abbrev-ref HEAD`; \
        if [ \"$current_branch\" = \"$branch\" ]; then \
          git reset --hard $commit; \
        else \
          git branch -Dq $branch; git branch $branch $commit; \
        fi; \
        echo 'Updated' $branch 'from' $old_commit 'to' $commit; \
      elif git merge-base --is-ancestor $commit $branch; then \
        echo 'Skipping' $branch 'which is ahead of bundle version ('$commit')'; \
      else \
        echo 'Error:' $branch 'already exists and diverges from upstream found in bundle'; \
        echo 'You could switch to the bundle version as follows, but you might lose work.'; \
        echo 'git checkout -B' $branch $commit; \
      fi; \
    else \
      git branch $branch $commit; \
      echo 'Created' $branch 'pointing at' $commit; \
    fi; done); }; f"

它从包中获取，然后尝试更新/创建其中包含的每个分支。如果您自己的分支版本在前面或等于，则什么也不做。如果该分支与包中的版本不同，则会打印一个错误，说明如何切换到包版本，而不做任何操作。

运行的例子，然后强制一个分支到包中的版本，然后重新运行，这没有任何作用：

$ git pullbundlebranches ../../bundles/Jabberwocky_November_snapshot.gitbundle
From ../../bundles/Jabberwocky_November_snapshot.gitbundle
 * branch              HEAD       -> FETCH_HEAD
../../bundles/Jabberwocky_November_snapshot.gitbundle is okay
Error: develop already exists and diverges from upstream found in bundle
You could switch to the bundle version as follows, but you might lose work.
git checkout -B develop 6c5214a7bd9b10d5f9e49ab9eadaa1533867ebb7
Created feature/all_glory_to_him pointing at 645152be25e0e5d3eb80615c9173e88714b23ade
Created feature/praise_the_lord pointing at 6c5214a7bd9b10d5f9e49ab9eadaa1533867ebb7
Created feature/why_are_you_reading_the_branch_names pointing at a55f5f74d6b129d173770e91c5a0ffe8ff981e8e

$ git checkout -B develop 6c5214a7bd9b10d5f9e49ab9eadaa1533867ebb7
Reset branch 'develop'
Your branch is up to date with 'origin/develop'.

$ git pullbundlebranches ../../bundles/Jabberwocky_November_snapshot.gitbundle
From ../../bundles/Jabberwocky_November_snapshot.gitbundle
 * branch              HEAD       -> FETCH_HEAD
../../bundles/Jabberwocky_November_snapshot.gitbundle is okay
Skipping develop which is up-to-date at 6c5214a7bd9b10d5f9e49ab9eadaa1533867ebb7
Skipping feature/all_glory_to_him which is up-to-date at 645152be25e0e5d3eb80615c9173e88714b23ade
Skipping feature/praise_the_lord which is up-to-date at 6c5214a7bd9b10d5f9e49ab9eadaa1533867ebb7
Skipping feature/why_are_you_reading_the_branch_names which is up-to-date at a55f5f74d6b129d173770e91c5a0ffe8ff981e8e