如何按行而不是列构建数据框架？

Question

a <- "dog cat carrot cabbage"
b <- "orange cat chair cabbage"
c <- "dog phone book beach"
x <- data.frame(a,b,c)
> x
                       a                        b                    c
1 dog cat carrot cabbage orange cat chair cabbage dog phone book beach

这是建在柱子上的。我想要的是一个1列数据帧，每个字符串都作为一行。我该怎么做？

Answer 1

d <- c(a,b,c)
data.frame(d)

输出：

                         d
1   dog cat carrot cabbage
2 orange cat chair cabbage
3     dog phone book beach

Answer 2

另一种选择是使用as.data.frame

as.data.frame(c(a,b,c))

#        c(a, b, c)
#1   dog cat carrot cabbage
#2   orange cat chair cabbage
#3   dog phone book beach

您也可以使用rbind

rbind(a, b, c)

#   [,1]                      
#a "dog cat carrot cabbage"  
#b "orange cat chair cabbage"
#c "dog phone book beach"  

Answer 3

可以逐行构建矩阵并将其转换为df。

data.frame(matrix(c(1, 7, 4, 6, 2, 0, 6, 2, 8), 3, 3, byrow = TRUE))