将正则表达式的匹配转换为多维数组

Question

下面的代码正确匹配：

• letter 'c' followed by digit
• letter 'c' followed by digit dash digit
• digit may be followed by an other digit enclosed in square parentheses []

并按预期创建一个数组，如下所示：

Array 
(
    [0] => Array
    (
        [start] => 4
        [end]=> 8
    )        
    [1] => Array
    (
        [start] => 2
        [end]=> 
    )
    [2] => Array
    (
        [start] => 3
        [end] => 5
    )
    [3] => Array
    (
        [start] => 6[2]
        [end] =>
    )
    [4] => Array
    (
        [start] => 8[4]
        [end] => 10
    )
    [5] => Array
    (
        [start] => 14
        [end] => 21[5]
    )
)

代码：

 $str = "a2c4-8|a6c2,c3-5,c6[2],c8[4]-10,c14-21[5]";

 $re = "~c(?<start>\d+(?:\[\d+])?)(?:-(?<end>(?&start)?))?~"; 

 $myarray = explode("|",$str);

foreach ($myarray as $my) {
    preg_match_all($re, $my, $matches);

    $res = array_map(function($ms, $me) { 
        return array("start" => $ms, "end" => $me);
    }, $matches["start"], $matches["end"]);
}

echo "<pre>";
    print_r($res);
echo "</pre>";

现在，我想在中添加一个，另一个值为a之后的数字的key。因此，例如，给定上面的$str

$str = "a2c4-8|a6c2,c3-5,c6[2],c8[4]-10,c14-21[5]". 

a值为：2和6，预期的结果数组如下。注意到，对于每个匹配的c， 6都是重复的。

Array 
(
    [0] => Array
    (
        [a] => 2
        [start] => 4
        [end]=> 8
    )        
    [1] => Array
    (
        [a] => 6
        [start] => 2
        [end]=> 
    )
    [2] => Array
    (
        [a] => 6
        [start] => 3
        [end] => 5
    )
    [3] => Array
    (
        [a] => 6
        [start] => 6[2]
        [end] =>
    )
    [4] => Array
    (
        [a] => 6
        [start] => 8[4]
        [end] => 10
    )
    [5] => Array
    (
        [a] => 6
        [start] => 14
        [end] => 21[5]
    )
)

Answer 1

你可以这样做：

$str = "a2c4-8|a6c2,c3-5,c6[2],c8[4]-10,c14-21[5]";

$re = '~(?:a(?<a>\d+))?c(?<start>\d+(?:\[\d+])?)(?:-(?<end>\g<start>))?~';

if (preg_match_all($re, $str, $matches, PREG_SET_ORDER) ) {
    $a = ''; // current value for "a" -----,
    $result = array_map(function ($i) use (&$a) {
        if (!empty($i['a'])) $a = $i['a'];
        else $i['a'] = $a;

        if (!isset($i['end'])) $i['end'] = '';

        foreach ($i as $k=>$v) {
            if (is_numeric($k)) unset($i[$k]);
        }

        return $i;

    }, $matches);
}

print_r($result);

但是，如果您已经确切地知道字符串的格式，并且不需要验证它，那么可能有更聪明(更快)的方法来获得相同的结果。

例如，将explode和格式化字符串与sscanf一起使用

$str = "a2c4-8|a6c2,c3-5,c6[2],c8[4]-10,c14-21[5]";

$parts = explode('|', $str);
$result = [];

$keys = ['a', 'start', 'end'];

foreach($parts as $part) {
    foreach(explode(',', $part) as $k=>$v) {
        if ($k)
            list($start, $end) = sscanf($v, 'c%[^-]-%[^,]');
        else
            list($a, $start, $end) = sscanf($v, 'a%dc%[^-]-%[^,]');

        $result[] = array_combine($keys, [$a, $start, $end]);
    }
}

print_r($result);