使用下划线、_.extend关键字的混合模式

Question

我想做一个基于“”的示例代码。

我有如下代码。

define(["jquery","underscore", "backbone"], function($, _,Backbone)  {

//Mixin :
//
/* Sometimes you have the same functionality for multiple objects 
 *      and it doesn’t make sense to wrap your objects in a parent object.
 * For example, if you have two views that share methods but don’t 
 *      – and shouldn’t – have a shared parent view.
 */

//I can define an object that has attributes and methods that can be shared across different classes.
//This is called a mixin.

//Mixin Object
var C = Backbone.Model.extend({
    c: function() {
        console.log("We are different but have C-Method shared");
    }
});

//To be Mixin-ed Object-1
var A = Backbone.Model.extend({
    a: 'A',
});

//To be Mixin-ed Object-2
var B = Backbone.Model.extend({
    b: 'B'
});

//underscore
_.extend(A.prototype, C);
_.extend(B.prototype, C);

return Backbone.Model.extend({
    initialize: function(){
        var testA = new A();
        testA.c();
        var testB = new B();
                    testA.c();

    }
});
});

如果我运行这段代码，就会出现一个错误：“testA.c不是函数”。从我研究过的一些示例代码来看，这应该是可行的。您能告诉我为什么这段代码不能尽可能详细地工作吗？

Answer 1

您的问题是复制C的属性而不是C.prototype的属性(方法c实际上是在这里定义的)。只需改变：

_.extend(A.prototype, C);
_.extend(B.prototype, C);

至：

_.extend(A.prototype, C.prototype);
_.extend(B.prototype, C.prototype);

一切都会如愿以偿。