错误: Slim实例必须是Slim\Views\Twig，Slim\Container给定

Question

我正在Youtube上尝试基本的容器教程，而我被困在了这个部分。我确保给出了一个小枝实例，而不是一个容器，但是错误仍然出现。

下面是index.php的容器部分：

$container['view'] = function ($container)
    {
    $view = new \Slim\Views\Twig('src/Views', ['cache' => false,]);
    $view->addExtension(new \Slim\Views\TwigExtension(
    $container->router,
    $container->request->getUri()
    ));

    return $view;
};

$container['loginController'] = function ($container){

    return new \App\Controllers\LoginController($container->view);
};

routes.php：

$app->get('/', 'LoginController:login_redirect');

controller.php：

 use Slim\Views\Twig as View;

protected $view;

public function __construct(View $view){
    $this->view = $view;

}

public function login_redirect($request, $response){
    $this->view->render($response, 'testing.twig');

}

Answer 1

这里不应该将$container['view']作为构造函数参数传递，而不是$container->view?

$container['loginController'] = function ($container){
    return new \App\Controllers\LoginController($container->view);
};