当使用mysqli_multi_query.But时,我能够从数据库中获得显示的值,我无法在HTML中打印,这可能是when循环的问题。下面是我的代码,它为三个SQL语句提供了AVG。唯一的问题是在HTML中显示平均值。
<?php
$con = new mysqli("localhost", "root","","survey");
if ($con){ printf(""); }
$query = "SELECT AVG(workarea) FROM score;" ;
$query .= "SELECT AVG(manager) FROM score;";
$query .= "SELECT AVG(comm) FROM score;";
// Execute multi query
if (mysqli_multi_query($con,$query)) {
do {
if ($result=mysqli_store_result($con)) {
// Fetch one and one row
while ($row=mysqli_fetch_row($result)) {
printf("%s\n",$row[0]);
}
// Free result set
mysqli_free_result($result);
}
} while (mysqli_next_result($con));
}
?>
<div class="row count">
WORK AREA/UNIT SCORE : <?php echo $row[0]; ?> // echo $row[AVG(workarea)] doesnot work
</div>
<div class="row count">
SUPERVISOR/MANAGER SCORE : <?php echo $row[0]; ?> // echo $row[AVG(manager)]
</div>
<div class="row count">
COMMUNICATION SCORE : <?php echo $row[0]; ?> // echo $row[AVG(comm)] doesnot work
</div>发布于 2016-06-14 06:23:30
不需要多个查询,只需在单个查询中获得AVG。并将html写入while循环中,如
$con = new mysqli("localhost", "root", "", "survey");
if ($con) {
printf("");
}
$query = "SELECT AVG(workarea),AVG(manager),AVG(comm) FROM score;";
// Execute multi query
if ($result = $con->query($query)) {
/* fetch object array */
while ($row = $result->fetch_row()) {
?>
<div class="row count">
WORK AREA/UNIT SCORE : <?php echo $row[0]; ?>
</div>
<div class="row count">
SUPERVISOR/MANAGER SCORE : <?php echo $row[1]; ?>
</div>
<div class="row count">
COMMUNICATION SCORE : <?php echo $row[2]; ?>
</div>
<?php
}
/* free result set */
$result->close();
}https://stackoverflow.com/questions/37804191
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