python联接列表2逐行列表1

Question

我有两个字符串列表，需要加入列表，因此列表2中的行被附加到列表1的每一行末尾。排序是正确的，每个列表中有相同数量的记录。例子如下：

list1 =  ["A", "B" , "C"]

list2 = ["E", "F", "G"]

newlist = ["A,E", "B,F", "C,G"]

Answer 1

只需简单地压缩列表，然后加入元组：

>>> list1 =  ["A", "B" , "C"]
>>> list2 = ["E", "F", "G"]
>>> [','.join(i) for i in zip(list1, list2)]
['A,E', 'B,F', 'C,G']

Answer 2

简单的任务，使用map

In[4]: list1 = ["A", "B" , "C"]

list2 = ["E", "F", "G"]
In[5]: newlist = map(lambda x, y: x+","+y, list1, list2)
In[6]: newlist
Out[6]: ['A,E', 'B,F', 'C,G']

您甚至可以为一般的长尾服务生成它：

def joinWithComma(*args):
    return ",".join(args)

In[15]: newlist = map(joinWithComma, list1, list2, list1, list2)
In[16]: newlist
Out[16]: ['A,E,A,E', 'B,F,B,F', 'C,G,C,G']

Answer 3

您可以结合列表理解和内置zip函数的强大功能：

In [1]: list1 =  ["A", "B" , "C"]

In [2]: list2 = ["E", "F", "G"]

In [3]: [a + ',' + b for a, b in zip(list1, list2)]
Out[3]: ['A,E', 'B,F', 'C,G']