中的表单不重定向到php。

Question

网站来源：http://www.salefee.com/

有人能查一下我上面提到的网站吗.我在“收卖故事电子书，提交你的电子邮件”下做了一份表格

我做了一个表单，用户提交他的电子邮件id，然后表单是链接到一个php文件发送电子邮件到用户电子邮件id。问题是表单没有被重定向到.php文件。我在HTML中添加了action和method属性。当用户单击submit按钮时，不会执行php代码。

HTML代码如下：

    <!-- Mailchimp Newsletter -->
              <div style="text-align:center">  
              <div class="newsletter-wrapper animateblock rtl-2 speed-1">
                <form action="story.php" method="post" class="form-inline subscription-mailchimp">
                  <div class="form-group input-group input-newsletter">
                    <input class="form-control" id="newsletter-email" name="newsletter-email" type="email" placeholder="Enter email">
                    <div class="input-group-btn">
                      <button class="btn btn-danger" type="submit">Sign Up</button>
                    </div>
                  </div>
                  </form>
                  <small class="help-block">Don't worry. We do not spam :)</small>
              </div>
              </div>
<!-- End Mailchimp Newsletter -->

我的php代码名为story.php，如下所示：

<?php
if ($_POST) {
  $to_email = "salefee12@gmail.com" //Recipient email, Replace with own email here


  //Sanitize input data using PHP filter_var().
  $user_trial_email   = filter_var($_POST["newsletter-email"], FILTER_SANITIZE_EMAIL);

  //additional php validation
  if (!filter_var($user_trial_email, FILTER_VALIDATE_EMAIL)) { //email validation
    $output = json_encode(array('type'=>'error', 'text' => 'Please enter a valid email.'));
    die($output);
  }

  //subject
  $subject = "The Story";

  //email body
  $message_body = "Email  : ".$user_trial_email."\r\nApp link:https://play.google.com/apps/testing/com.salefee.salefee.salefee\r\nWe will shortly send you the whole story";

  //proceed with PHP email.
  $headers = 'From: '."salefee12@gmail.com".''."\r\n".
  'Reply-To: '.$user_trial_email.''."\r\n".
  'X-Mailer: PHP/'.phpversion();

  $send_mail = mail($to_email, $subject, $message_body, $headers);

  if (!$send_mail)
  {
    //If mail couldn't be sent output error. Check your PHP email configuration (if it ever happens)
    $output = json_encode(array('type'=>'error', 'text' => 'Could not send mail! Please check your PHP mail configuration.'));
    die($output);
  } else {
    $output = json_encode(array('type'=>'message', 'text' => 'Hi '.$user_trial_name.', Thank you for subscribing. You will soon get a link to download app.'));
    die($output);
  }
}
?>

有人能帮我把这个code...Thanks提前！

Answer 1

首先，您需要为提交按钮指定名称：

<button class="btn btn-danger" type="submit" name="submit">Sign Up</button>

然后在php文件中：

if (isset($_POST("submit")) {

Answer 2

PHP:

if ($_POST['signup']) {
//your script which you want to execute as soon as form submitted
}

HTML:

<button class="btn btn-danger" type="submit" name="signup">Sign Up</button>

了解有关如何使用$_POST[]的更多信息

http://php.net/manual/en/reserved.variables.post.php

Answer 3

在PHP中，数据是通过名称而不是id传递的。所以HTML代码应该如下所示

<input class="form-control" id="newsletter-email" **name**="newsletter-email" name="newsletter-email" type="email" placeholder="Enter email">

如果您得到这样的数据，那么PHP文件应该可以工作。

$_POST["newsletter-email"]