如何对LSTM网络进行像素级分类?特别是在Tensorflow。
我的直觉告诉我,输出张量(代码中的pred &y )应该是与输入图像具有相同分辨率的二维张量。换句话说,输入图像为200x200,输出分类为200x200。
Udacity课程包括输入图像为28x28的LSTM网络示例。然而,它是一个图像(作为一个整体手写MNIST数据集)分类网络.
我的想法是,我可以用维度[n_classes]替换所有张量,使用[n_input][n_steps] (下面的代码)。然而,它在矩阵乘法中抛出一个错误。
Udacity示例代码部分如下所示:
n_input = 28 # MNIST data input (img shape: 28*28)
n_steps = 28 # timesteps
n_hidden = 128 # hidden layer num of features
n_classes = 10 # MNIST total classes (0-9 digits)
# tf Graph input
x = tf.placeholder("float", [None, n_steps, n_input])
y = tf.placeholder("float", [None, n_classes])
# Define weights
weights = {
'hidden': tf.Variable(tf.random_normal([n_input, n_hidden])),
'out': tf.Variable(tf.random_normal([n_hidden, n_classes]))
}
biases = {
'hidden': tf.Variable(tf.random_normal([n_hidden])),
'out': tf.Variable(tf.random_normal([n_classes]))
}
def RNN(x, weights, biases):
# Prepare data shape to match `rnn` function requirements
# Current data input shape: (batch_size, n_steps, n_input)
# Permuting batch_size and n_steps
x = tf.transpose(x, [1, 0, 2])
# Reshaping to (n_steps*batch_size, n_input)
x = tf.reshape(x, [-1, n_input])
# Split to get a list of 'n_steps' tensors of shape (batch_size, n_hidden)
# This input shape is required by `rnn` function
x = tf.split(0, n_steps, x)
# Define a lstm cell with tensorflow
lstm_cell = rnn_cell.BasicLSTMCell(n_hidden, forget_bias=1.0)
pdb.set_trace()
# Get lstm cell output
outputs, states = rnn.rnn(lstm_cell, x, dtype=tf.float32)
# Linear activation, using rnn inner loop last output
return tf.matmul(outputs[-1], weights['out']) + biases['out']
pred = RNN(x, weights, biases)然后我的代码看起来如下:
n_input = 200 # data data input (img shape: 28*28)
n_steps = 200 # timesteps
n_hidden = 128 # hidden layer num of features
n_classes = 2 # data total classes (0-9 digits)
# tf Graph input
x = tf.placeholder("float", [None, n_input, n_steps])
y = tf.placeholder("float", [None, n_input, n_steps])
# Define weights
weights = {
'hidden': tf.Variable(tf.random_normal([n_input, n_hidden]), dtype="float32"),
'out': tf.Variable(tf.random_normal([n_hidden, n_input, n_steps]), dtype="float32")
}
biases = {
'hidden': tf.Variable(tf.random_normal([n_hidden]), dtype="float32"),
'out': tf.Variable(tf.random_normal([n_input, n_steps]), dtype="float32")
}
def RNN(x, weights, biases):
# Prepare data shape to match `rnn` function requirements
# Current data input shape: (batch_size, n_steps, n_input)
# Permuting batch_size and n_steps
pdb.set_trace()
x = tf.transpose(x, [1, 0, 2])
# Reshaping to (n_steps*batch_size, n_input)
x = tf.reshape(x, [-1, n_input])
# Split to get a list of 'n_steps' tensors of shape (batch_size, n_hidden)
# This input shape is required by `rnn` function
x = tf.split(0, n_steps, x)
# Define a lstm cell with tensorflow
lstm_cell = rnn_cell.BasicLSTMCell(n_hidden, forget_bias=1.0)
pdb.set_trace()
# Get lstm cell output
outputs, states = rnn.rnn(lstm_cell, x, dtype=tf.float32)
# Linear activation, using rnn inner loop last output
# return tf.matmul(outputs[-1], weights['out']) + biases['out']
return tf.batch_matmul(outputs[-1], weights['out']) + biases['out']
pred = RNN(x, weights, biases)return tf.batch_matmul(outputs[-1], weights['out']) + biases['out']行就是问题所在。因为outputs是二维张量的向量,而weights['out']是三维张量的向量。
我想也许我可以改变outputs的维度,但是这需要深入到RNN对象中(在API中)。
我在这里有什么选择?我能做些整形吗?如果是这样的话,我应该重塑什么,以什么方式?
发布于 2016-06-07 22:05:43
您不能使用维数为3的形状[n_hidden, n_input, n_step]的矩阵进行矩阵乘法。
您可以做的是输出一个维度[batch_size, n_input * n_step]的向量,然后将其重塑回[batch_size, n_input, n_step]。
weights = {
'hidden': ... ,
'out': tf.Variable(tf.random_normal([n_hidden, n_input * n_steps]), dtype="float32")
}
biases = {
'hidden': ... ,
'out': tf.Variable(tf.random_normal([n_input * n_steps]), dtype="float32")
}
# ...
pred = RNN(x, weights, biases)
pred = tf.reshape(pred, [-1, n_input, n_steps])在你的模型上
但是,您在这里所做的是对图像的每一列都使用RNN。您正在尝试获取图像的每个部分(总共200),并迭代它,这根本不会给出好的结果。
如果您想要处理图像,我建议您查看一下来自TensorFlow的TensorFlow,在那里您可以学习如何在图像上使用卷积,这比RNN有效得多。
https://stackoverflow.com/questions/37689920
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