快速变回原来的json结构

Question

我已经将一个严格的json对象从javascript传递给了swift。

js

'use strict';

var labdetail = function()
{
var labs = ["sdsdsd","suds","DH-sdsd","DH-sdsd"]
var labgrp = {labGrp:"R", labGrpDesc:"sdsd",labs:labs}
var labGroups = []
labGroups[0] = labgrp
var labs1 = ["dsdsd","suds","DH-sdsd","DH-dfdf]
var labgrp1 = {labGrp:"H", labGrpDesc:"dfdf",labs:labs}
labGroups[1] = labgrp1
return JSON.stringify(labGroups);

}

swift

import UIKit
import JavaScriptCore
class ViewController: UIViewController {

override func viewDidLoad() {
    super.viewDidLoad()
    let context = JSContext()
    let returnLabResultJSPath = NSBundle.mainBundle().pathForResource("returnLabResult", ofType: "js")
    let contentData = NSFileManager.defaultManager().contentsAtPath(returnLabResultJSPath!)
    let content = NSString(data: contentData!, encoding: NSUTF8StringEncoding) as? String
   //     let returnresult = try String(contentsOfFile: returnLabResultJSPath!, encoding: NSUTF8StringEncoding)
    context.evaluateScript(content)
    let getlabfunction =  context.objectForKeyedSubscript("labdetail")
    var labresult = getlabfunction.callWithArguments([])
    let labresultdict :dictionary = labresult.toDictionary()

    print(labresult)

}

我想把它改回原来的结构。我试着使用todictionary()，但失败了

现在实验室的结果是[{{“labGrp”：“R”，“labGrpDesc”：“悲伤”，“实验室”：“悲伤”，"asdasd"，“sadsad”，"DH-asdasd"}，{"labGrp":"H"，“labGrpDesc”：“生物学”，“实验室”："asdsad"，“asd桑”，“和”，"DH-asdasd"}]。

我希望它是一个数组，并且数组包含{"labGrp":"R"，“labGrpDesc”：“悲伤”，“实验室”：“悲伤”，"asdasd"，“sadsad”，"DH-asdasd"}

array1包含{"labGrp":"H"，“labGrpDesc”：“生物学”，“实验室”："asdsad"，“asdsad”，" and "，"DH-asdasd"}

Answer 1

希望您需要反序列化JSon对象，然后它会生成Dictionary对象。

例如：

      var labresult = getlabfunction.callWithArguments([])

        do{
            if let data = labresult.dataUsingEncoding(NSUTF8StringEncoding) {
                let json = try NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions()) as? [String:String]
          }catch{  }