将字典复制到Swift中的数组中

Question

我试图使用[String:AnyObject]创建一个字典数组。我使用SwiftyJSON将JSON转换为JSON对象，并能够循环遍历每个键和值。下面的代码将不会为每个企业创建一个单独的业务，而是为每个业务中的每个键和价值创建一个单独的业务。目前，JSON有关于id、name、纬度和经度的部分，我希望在字典中为数组中的每个业务提供这些值。

var businesses = [[String:AnyObject]]()

for business in json["businesses"]!.array! {
    for (key,value) in business {
        let value1 = value.stringValue
        businesses.append([key:value1])
    }
}

如何调整此代码以为每个业务创建单个业务，而不是为每个键和值在数组中创建单个业务。

目前：

businesses[:] = ["id" = 1, "name" = "asdf",...,"id" = 2, "name" = "asdf2"] 

而不是我想要的

businesses[0] = ["id" = 1, "name" = "asdf"]
businesses[1] = ["id" = 2, "name" = "asdf2"]

Answer 1

基本上，您只需要将每个业务的键、值对添加到字典中，然后将该字典添加到数组中。

就像这样：

var businesses = [[String: AnyObject]]
        for business in json["businesses"]!.array! {
            var dic = [String: AnyObject]
            for (key,value) in business {
                let value1 = value.stringValue
                dic [key] = value1
            }
            businesses.append(dic)
        }

因为您没有提供JSON数据，所以我无法100%地测试代码，但这是一般的想法。

Answer 2

在游乐场上运行这个。

//: Playground - noun: a place where people can play
import UIKit

// Simulating JSON
class sim {
    let s: String
    init(_ s:String) {self.s = s}
    var stringValue:String {return s}
}
let simulatingJSONThings = [
    ["id":sim("3"), "name":sim("Alice"), "lat":sim("123.45"), "lng":sim("567.89")],
    ["id":sim("4"), "name":sim("Bob"), "lat":sim("123.45"), "lng":sim("567.89")],
    ["id":sim("5"), "name":sim("Conny"), "lat":sim("123.45"), "lng":sim("567.89")],
]

// #1 Yours
do {
    var businesses = [[String:AnyObject]]()
    for business in simulatingJSONThings {
        for (key,value) in business {
            let value1 = value.stringValue
            businesses.append([key:value1])
        }
    }
    businesses
}

// #2 Answer
do {
    var businesses = [[String:AnyObject]]()
    for business in simulatingJSONThings {
        var b = [String:String]()
        for (key,value) in business {
            let value1 = value.stringValue
            b[key] = value1
        }
        businesses.append(b)
    }
    businesses
}