我尝试用类似于Features2D +查找已知对象的单形的方法来比较图像,但是用自写的findAffine()函数代替findHomography()。
利用塞莱斯·索尔弗方法得到了考虑离群点的最优仿射矩阵。
double translation[] = {0, 0};
double angle = 0;
double scaleFactor = 1;
ceres::Problem problem;
for (size_t i = 0; i < points1.size(); ++i) {
problem.AddResidualBlock(
new ceres::AutoDiffCostFunction<AffineResidual, 1, 2, 1, 1>(
new AffineResidual(Eigen::Vector2d(points1[i].x, points1[i].y),
Eigen::Vector2d(points2[i].x, points2[i].y))),
new ceres::HuberLoss(1.0),
translation,
&angle,
&scaleFactor);
}
ceres::Solver::Options options;
options.linear_solver_type = ceres::DENSE_QR;
options.minimizer_progress_to_stdout = true;
ceres::Solver::Summary summary;
Solve(options, &problem, &summary);Ceres解算器提供LossFunction
损失函数减少了高残差残差块的影响,通常是对应于离群点的残差块。
当然,我可以用得到的矩阵从第一幅图像中转换关键点坐标,并与第二次进行比较,得到偏差。但在工作过程中,塞勒斯的解决者已经在里面完成了。
我怎么才能找回它?在文件中没有找到。
发布于 2016-06-08 14:44:20
我也有过类似的问题。在查看了Ceres库源(特别是ResidualBlock::估价()方法)之后,我得出了一个结论,即对于剩余块,没有明显的“离群点”状态。损失函数似乎只影响块的最终成本值(正如您引用的文档中的短语所描述的那样-“损失函数减少了具有高残差的剩余块的影响”)。所以答案是,你不能从谷神星中检索离群值,没有这样的特征。
解决方法可能是用已解决的结果计算数据的剩余值,并将损失函数应用于它们。来自LossFunction::might ()的评论可能会有所帮助:
// For a residual vector with squared 2-norm 'sq_norm', this method
// is required to fill in the value and derivatives of the loss
// function (rho in this example):
//
// out[0] = rho(sq_norm),
// out[1] = rho'(sq_norm),
// out[2] = rho''(sq_norm),
//
// Here the convention is that the contribution of a term to the
// cost function is given by 1/2 rho(s), where
//
// s = ||residuals||^2.
//
// Calling the method with a negative value of 's' is an error and
// the implementations are not required to handle that case.
//
// Most sane choices of rho() satisfy:
//
// rho(0) = 0,
// rho'(0) = 1,
// rho'(s) < 1 in outlier region,
// rho''(s) < 0 in outlier region,
//
// so that they mimic the least squares cost for small residuals.
virtual void Evaluate(double sq_norm, double out[3]) const = 0;https://stackoverflow.com/questions/37379557
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