NoReverseMatch展示/成功/成功

Question

在get_success_URL的FileView方法中，我使用了‘display: redirected’作为要重定向的URL。但是我收到了一个错误

Reverse for 'redirect' with arguments '()' and keyword arguments '{'pk': 15}' not found. 1 pattern(s) tried: ['display/success/']

请求方法: POST请求URL：http://127.0.0.1:8000/display/upload/ Django版本: 1.10.dev20160512164014异常类型: NoReverseMatch异常值：

我是不是遗漏了什么？

display/views.py

class FileView(FormView):

    template_name = 'display/upload.html'
    form_class = FileForm

    def form_valid(self, form):

        file_upload = FileModel(file=self.get_form_kwargs().get('files')['file'])
        file_upload.save()
        self.id = file_upload.id

        return HttpResponseRedirect(self.get_success_url())

    def get_success_url(self):

        return reverse('display:redirect', kwargs={'pk': self.id})

def redirect(request):

    return render(request,"display/success.html")

display/urls.py

from django.conf.urls import url
from django.conf.urls.static import static
from django.conf import settings

from . import views

from display.views import FileView

urlpatterns = [
    url(r'^start/', views.initial,name='home'),
    url(r'^upload/',FileView.as_view(),name='upload'),
    url(r'^success/',views.redirect,name='redirect'),
] + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)

Answer 1

看看这一行：

Reverse for 'redirect' with arguments '()' and keyword arguments '{'pk': 15}' not found.

错误信息是告诉你出了什么问题。您已经传递了一个关键字参数，当它试图反向/查找url时，它不会传递，因为您的url被指定为：

url(r'^success/',views.redirect,name='redirect')

不接受任何争论。一种可能是让你的网址变成这样：

^success/(?P<pk>\d+)/$