从milliSeconds字符串中删除iOS

Question

尝试从字符串(日期)中删除毫秒

NSString *dateString = @"2016-05-16 13:17:34.674194";
 NSDateFormatter* formater = [[NSDateFormatter alloc] init];
 [formater setDateFormat:@"dd/MM/yyyy HH:mm:ss"];
 NSDate *date = [formater dateFromString:dateString];
 NSLog(@"%@",[formater stringFromDate:date]);

而我却变得一无所有

我在期待类似的结果(用掉几千秒)

"06/05/2016 13:17:34“

请建议..。

Answer 1

复制并粘贴此代码，运行良好

NSString *dateString = @" ";
NSDateFormatter* dateFormatter1 = [[NSDateFormatter alloc] init];
dateFormatter1.dateFormat = @"yyyy-MM-dd HH:mm:ss.SSS";
NSDate *yourDate = [dateFormatter1 dateFromString:dateString];
dateFormatter1.dateFormat = @"dd/MM/yyyy HH:mm:ss";
NSLog(@"%@",[dateFormatter1 stringFromDate:yourDate]);

这是输出

2016-05-16 16:43:53.639 StackLearn[6376:151614] 16/05/2016 13:17:34

日期格式化程序的规则是，在从字符串获取日期时，必须设置与字符串相同的日期格式，如果不匹配，则将获得null。

Answer 2

试试这个：-

NSString *dateString = @"2016-05-16 13:17:34.674194";
NSDateFormatter* dateFormatter = [[NSDateFormatter alloc] init];
dateFormatter.dateFormat = @"yyyy-MM-dd HH:mm:ss.SS";     
NSDate *yourDate = [dateFormatter dateFromString:dateString];
dateFormatter.dateFormat = @"dd-MMM-yyyy HH:mm:ss";
NSLog(@"%@",[dateFormatter stringFromDate:yourDate]);

Answer 3

工作完美

NSString *dateString = @" ";
NSDateFormatter* dateFormatter1 = [[NSDateFormatter alloc] init];
dateFormatter1.dateFormat = @"yyyy-MM-dd HH:mm:ss.SSS";
NSDate *yourDate = [dateFormatter1 dateFromString:dateString];
dateFormatter1.dateFormat = @"dd/MM/yyyy HH:mm:ss";
NSLog(@"%@",[dateFormatter1 stringFromDate:yourDate]);