#include <mhash.h>
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
int i;
MHASH td;
unsigned char buffer;
unsigned char *hash;
td = mhash_init(MHASH_WHIRLPOOL);
if (td == MHASH_FAILED) exit(1);
while (fread(&buffer, 1, 1, stdin) == 1) {
mhash(td, &buffer, 1);
}
hash = mhash_end(td);
for (i = 0; i < mhash_get_block_size(MHASH_WHIRLPOOL); i++) {
printf("%.2x", hash[i]);
}
printf("\n");
exit(0);
}嗨,我有上面的代码从mhash示例页面。我需要修改它,所以它将继续从stdin读取,并逐行计算哈希值,而不是等待EOF
cat textfile | whirlpool_line_hash我的理解是,我保留while循环(等待EOF),并在收到10 (0x0a)后进行哈希计算和打印。打印后的mhash需要重置,对吗?我对C一点也不感兴趣,但我需要一个快速的程序,所以我想用C来实现它。我已经无法将指针与整数进行比较了;-)有人能帮忙吗?
发布于 2016-05-09 10:30:59
除了一个小小的警告之外,它可以工作,mhash_end返回的mhash_end缓冲区是一个动态分配的缓冲区,所以当您使用它时最好使用它:
free(hash);您可以使用fgets,它最多只读取一行。就性能而言,每次读取和输入散列( char )可能不是最好的方法,相反,您可以读取整行并将块输入散列函数进行更新。试试这个:
char line[4096];
int len;
while (fgets(line, sizeof line, stdin) != NULL) { // read a line each time
len = strlen(line);
char *p = strrchr(line, '\n');
if (p != NULL)
mhash(td, line, len - 1); // strip the new line
else
mhash(td, line, len);
}
hash = mhash_end(td);
for (i = 0; i < mhash_get_block_size(MHASH_WHIRLPOOL); i++) {
printf("%.2x", hash[i]);
}
free(hash);发布于 2016-05-09 10:25:24
做到了;-)
#include <mhash.h> //mhash
#include <stdio.h>
#include <stdlib.h> //exit
#include <unistd.h> //getopt
int main(void)
{
int i;
MHASH td;
unsigned char buffer;
unsigned char *hash;
td = mhash_init(MHASH_WHIRLPOOL);
if (td == MHASH_FAILED) exit(1);
while (fread(&buffer, 1, 1, stdin) == 1) { // read from stdin until receive EOF
if ( buffer != '\n' ) { mhash(td, &buffer, 1); } //dont calculate line break
if ( buffer == '\n' ) { //received line break
hash = mhash_end(td);
for (i = 0; i < mhash_get_block_size(MHASH_WHIRLPOOL); i++) { printf("%.2x", hash[i]); }
printf("\n");
td = mhash_init(MHASH_WHIRLPOOL);
}
}
exit(0);
}https://stackoverflow.com/questions/37112856
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