我正在尝试创建一个属性,它将以不同的方式序列化从操作返回的数据
public override void OnActionExecuted(HttpActionExecutedContext filterContext)
{
var content = (filterContext.Response.Content as ObjectContent);
if (content == null)
{
return;
}
if (content.ObjectType.IsGenericType
&& content.ObjectType.GetGenericTypeDefinition() == typeof (Page<>))
{
var pageObject = (content.Value as IPage);
var jsonFormatterRule = new JsonFormatterRule();
var pageJson = JsonConvert.SerializeObject(pageObject.ItemsArray,
jsonFormatterRule.GetPascalCasedSettings());
//How do I set the content that \/ doesn't compile?
//filterContext.Response.Content = pageJson;
}
}这是JsonFormatterRules,以防有人想见他们。
public JsonSerializerSettings GetDefaultSettings()
{
var settings = new JsonSerializerSettings()
{
Formatting = Formatting.Indented,
ContractResolver = new CamelCasePropertyNamesContractResolver(),
DateTimeZoneHandling = DateTimeZoneHandling.RoundtripKind,
};
settings.Converters.AddRange(defaultConfiguredConverters);
return settings;
}
public JsonSerializerSettings GetPascalCasedSettings()
{
var settings = this.GetDefaultSettings();
settings.ContractResolver = new DefaultContractResolver();
return settings;
}如何设置执行的On的内容?我不能全局地将默认序列化程序更改为DefaultContract,因为它可能会导致线程问题。
此外,我不希望创建一个新的响应,并复制从旧的标题,似乎超过杀死。
发布于 2016-05-05 15:49:06
这样做的一种方法是定义自定义格式化程序。
首先,定义属性:
[AttributeUsage(AttributeTargets.Class)]
public sealed class SpecialSerializeAttribute : Attribute
{
}现在创建一个将找到属性的格式化程序:
public class SpecialSerializeFormatter : MediaTypeFormatter
{
public SpecialSerializeFormatter()
{
//You can add any other supported types here.
this.SupportedMediaTypes.Add(new MediaTypeHeaderValue("application/json"));
}
public override bool CanReadType(Type type)
{
//you can just return false if you don't want to read any differently than your default way
//if you return true here, you should override the ReadFromStreamAsync method to do custom deserialize
return type.IsDefined(typeof(SpecialSerializeAttribute), true));
}
public override bool CanWriteType(Type type)
{
return type.IsDefined(typeof(SpecialSerializeAttribute), true));
}
public override async Task WriteToStreamAsync(Type type, object value, Stream writeStream, HttpContent content,
TransportContext transportContext)
{
//value will be your object that you want to serialize
//add any custom serialize settings here
var json = JsonConvert.SerializeObject(value);
//Use the right encoding for your application here
var byteArray = Encoding.UTF8.GetBytes(json);
await writeStream.WriteAsync(byteArray, 0, byteArray.Length);
}
}在您的WebApiConfig.cs中注册格式化程序
您还可以直接为每种类型构建一个格式化程序,然后不必执行该属性。只需更改CanRead和CanWrite方法即可。我发现基于这些直接类型提供了更好的结果,因为它不是这样的通用格式化程序,您可能需要根据类型应用自定义逻辑,但是上面的答案应该可以满足您的需要。
发布于 2016-05-05 16:55:41
如果有人想知道,响应内容是一个HTTPContent,它继承自ByteArrayContent。因此,如果已经序列化了JSON,则只需将其放入字节数组中即可。
filterContext.ActionContext.Response.Content = new ByteArrayContent(Encoding.ASCII.GetBytes(pageJson));https://stackoverflow.com/questions/37054236
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