如何在sap.m.list中对过滤项进行裁剪

Question

我已经有了一个sap.m.list，它已经基于一个property.Now进行了过滤，我再次需要为该列表应用过滤器来实现实时搜索。

filterList:function(evt){
        debugger;
        var filters = [];
         var oFilter="";
        var query = evt.oSource.mProperties.value;
        if (query && query.length > 0) {
            var filter = new sap.ui.model.Filter("CLTYPE", sap.ui.model.FilterOperator.Contains, query);
            filters.push(filter);

            var filter1 = new sap.ui.model.Filter("CLCAT", sap.ui.model.FilterOperator.Contains, query);
            filters.push(filter1);
            var filter2 = new sap.ui.model.Filter("CLNUM", sap.ui.model.FilterOperator.Contains, query);
            filters.push(filter2);

            oFilter = new sap.ui.model.Filter( filters, false );
        }


        // update list binding
        var list = sap.ui.getCore().byId("List");
        var binding = list.getBinding("items");
        binding.filter(oFilter);
    },

在这里，我的列表已经是filtered.here list.getBinding(' items ')了，它将给我所有的条目，而不是过滤的items。

     obj[filterParam] = context;

    var contextClauses=_.where(clauses,obj);
    sap.ui.getCore().getModel('ClauseModel').setProperty("/DATA/CURRENTCLAUSES",contextClauses);

// update list binding
var list = sap.ui.getCore().byId("List");
var binding = list.getBinding("items");
binding.filter(oFilter);

如何实施？？有什么建议吗？

Answer 1

我用过滤器中的'and‘条件来解决它

 var mainFilter=new sap.ui.model.Filter(parameter,sap.ui.model.FilterOperator.Contains,context);
        var query =evt.getParameter("newValue");
        if (query && query.length > 0)var filter1= new sap.ui.model.Filter("CLNAME",sap.ui.model.FilterOperator.Contains,query);
            filtersArr1.push(filter1);
            filtersArr1.push(mainFilter);
          var filter2 = new sap.ui.model.Filter("CLNUM",sap.ui.model.FilterOperator.Contains, query);
            filtersArr2.push(filter2);
            filtersArr2.push(mainFilter);oFilter1 = new sap.ui.model.Filter(filtersArr1,true);oFilter2 = new sap.ui.model.Filter(filtersArr2,true);filterGroup.push(oFilter1,oFilter2);oFilter4 = new sap.ui.model.Filter(filterGroup,false);
            binding.filter(oFilter4);

工作精良

Answer 2

将livechange添加到textfield中，并调用一个函数来筛选列表。

new sap.ui.commons.TextField({type:"Text",
        value:"",
        liveChange: function(oEvent){   
        //Now call a function to filter your list.                                       
        filterList(oEvent,oStorage.get("previousFilteredList"));
        }});
        filterList: function(oEvent,yourObj){  
                  var like = oEvent.getParameter("liveValue");  
                  var oFilter = new sap.ui.model.Filter("name",   
                  sap.ui.model.FilterOperator.StartsWith,like);  
                  var element = sap.ui.getCore().getElementById("sample");  
                  var listBinding = element.getBinding("items");  
                  listBinding.filter([oFilter]);  
  //Add the filtered object oStorage after every filter to access the previous filtered data
                //oStorage.put("previousFilteredList","yourobj");  
        }, 
    //Wherever you filter your data first.
    oStorage = jQuery.sap.storage("session");
    oStorage.put("previousFilteredList","yourobj");

Answer 3

我想你有两个选择：

1. 应用原始筛选器，然后应用附加筛选器。
2. 为最初筛选的列表创建一个新实例： //假设您已经声明了列表(initialList和newList) // <..>之间的值应该替换为jQuery.each (initialList、function (索引)、item) { if (item )。== ){ //您可以向新的列表项添加一个附加字段，如: item"= ){newList.push(项)；//将此项添加到新的数组/列表} newListModel.setData(newList)；//假定newListModel已创建//绑定到控件