我正在制作一张像下面这样的桌子。
create table modifications (
id bigint(20) AUTO_INCREMENT not null primary key,
type varchar(100),
user_id bigint(20) null,
vulnerability_id bigint(20) null
)
alter table modifications
add constraint fk_user_id foreign key (user_id) references app_user(id)
alter table modifications
add constraint fk_vulnerability_id foreign key (vulnerability_id) references vulnerabilities(id)
alter table modifications
add constraint ck_OneIsNotNull check (user_id is not null or vulnerability_id is not null)
alter table modifications
add constraint ck_OneIsNull check (user_id is null or vulnerability_id is null)我的目标是列之一应该为空,另一列不应该为空。但是,当我同时插入null或null时,它是接受的,没有抛出错误。下面是我使用的insert查询。
insert into modifications (type,user_id,vulnerability_id) values('vulnerability',16,65)
insert into modifications (type) values('vulnerability')我哪里出错了?
发布于 2016-04-29 03:38:49
MySQL不强制执行检查约束。
这在MySQL参考手册中有记录。
您可以创建一个“前插入”和“更新前”触发器,以强制执行这样的约束。
例如:
DELIMITER $$
CREATE TRIGGER modifications_bi
BEFORE INSERT ON modifications
FOR EACH ROW
BEGIN
IF ( NEW.user_id IS NULL AND NEW.vulnerability_id IS NULL )
OR ( NEW.user_id IS NOT NULL AND NEW.vulnerability_id IS NOT NULL ) THEN
SIGNAL SQLSTATE '45000'
SET MESSAGE_TEXT = 'Error: one must be null and one must be non-null';
END IF;
END$$
DELIMITER ;如果在5.5之前运行版本,则不支持信号语法。若要抛出异常,则需要运行导致异常的SQL语句。
https://stackoverflow.com/questions/36929112
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