如何在java中使用以下CURL命令？

Question

这是URL

curl -H“授权:无记名oVi4yPxk1bJ64Y2qOsLJ2D2ZlC3FpK4L”https://api.url.com/v1/market/total-items.json

我想在JAVA上使用它，其中oVi4yPxk1bJ64Y2qOsLJ2D2ZlC3FpK4L值将是我使用变量接收到的一个动态值。

Answer 1

在Java中就是这样做的。curl -h由httpPost.addHeader() curl由表单curl -u负责，至少在这个API (例如条带)的情况下，它是授权行者。在Oauth2的情况下，curl -u在头文件中传递用户名:密码。

form.add(new BasicNameValuePair("username", request.getParameter("username")));

CloseableHttpClient userWebTokenHTTPclient;
        if (HIFIConstants.FULL_URL_HIFINITE.contains("localhost")) {  //for localhost HTTP request fails due to certificate issues, hence workaround. Works for Beta etc without SSLContext

            SSLContextBuilder sslcontext = new SSLContextBuilder();
            sslcontext.loadTrustMaterial(null, new TrustSelfSignedStrategy());
            userWebTokenHTTPclient = HttpClients.custom().setSSLContext(sslcontext.build()).setSSLHostnameVerifier(NoopHostnameVerifier.INSTANCE)
                    .build();
        } else
            userWebTokenHTTPclient = HttpClients.createDefault();



        HttpPost httpPost = new HttpPost("https://api.somepublicsite.com/v1/ident/verits");

        List<NameValuePair> form = new ArrayList<>();
        form.add(new BasicNameValuePair("return_url", "https://example-dev.example.com?vi={VERIFICATION_INTENT_ID}"));
        form.add(new BasicNameValuePair("requested_verifications[0]", "identity_document"));
        UrlEncodedFormEntity entity = new UrlEncodedFormEntity(form, Consts.UTF_8);
        httpPost.setEntity(entity);

        httpPost.addHeader("Authorization", "Bearer somesecretkeyhere"); 
        httpPost.addHeader("Version", "v3");
        httpPost.addHeader("Content-type", "application/x-www-form-urlencoded");    
        CloseableHttpResponse tokenResponse = userWebTokenHTTPclient.execute(httpPost);
        org.json.JSONObject verificationIntent = new org.json.JSONObject(EntityUtils.toString(tokenResponse.getEntity()));
        userWebTokenHTTPclient.close();